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3 changes: 3 additions & 0 deletions contains-duplicate/WHYjun.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,3 @@
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
return len(set(nums)) != len(nums)
21 changes: 21 additions & 0 deletions house-robber/WHYjun.py
Original file line number Diff line number Diff line change
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class Solution:
def rob(self, nums: List[int]) -> int:
# memo for DP
dp = {}
return self.robs(nums, dp, len(nums) - 1)

def robs(self, nums: List[int], dp: Dict[int, int], houseToRob: int) -> int:
if houseToRob < 0:
return 0

if houseToRob - 2 not in dp:
dp[houseToRob - 2] = self.robs(nums, dp, houseToRob - 2)

if houseToRob - 1 not in dp:
dp[houseToRob - 1] = self.robs(nums, dp, houseToRob - 1)


return max(
dp[houseToRob - 2] + nums[houseToRob],
dp[houseToRob - 1]
)
44 changes: 44 additions & 0 deletions longest-consecutive-sequence/WHYjun.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,44 @@
import heapq

class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
# remove duplicates by using set
numsSet = set(nums)

if len(numsSet) == 0 or len(numsSet) == 1:
return len(numsSet)

# Use priority queue to sort in O(n)
pq = heapq.heapify(list(numsSet))

prev = heapq.heappop(pq)
answer, count = 1, 1
for i in range(len(numsSet) - 1):
popped = heapq.heappop(pq)
if prev + 1 == popped:
count += 1
else:
count = 1

prev = popped
answer = max(answer, count)

return answer

def longestConsecutiveUsingSetOnly(self, nums: List[int]) -> int:
# remove duplicates by using set
numsSet = set(nums)

answer = 0

for num in numsSet:
# continue if it's not the longest consecutive
if num - 1 in numsSet:
continue
else:
count = 1
while num + count in numsSet:
count += 1
answer = max(answer, count)

return answer
17 changes: 17 additions & 0 deletions top-k-frequent-elements/WHYjun.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
class Solution:
def topKFrequent(self, nums: List[int], k: int) -> List[int]:
# Time complexity: O(nlog(n))
# Space Complexity: O(n)

if len(nums) <= k:
return list(set(nums))

counts = {}
for num in nums:
if num not in counts:
counts[num] = 0
counts[num] += 1

# The key of dictionary is unique.
sortedKeys = sorted(list(counts.keys()), key=lambda key: counts[key], reverse = True)
return sortedKeys[:k]
12 changes: 12 additions & 0 deletions two-sum/WHYjun.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
memo = {}

for i, num in enumerate(nums):
diff = target - num
if diff in memo:
# Each input would have exactly one solution
return [memo[diff], i]
memo[num] = i

return []