fix: Infer parameter type from default value when no explicit type annotation#476
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danadajian merged 1 commit intomainfrom May 5, 2026
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…esent When a function parameter has a default value but no explicit TypeScript type annotation (e.g. `input1 = 123`), the generated interface now infers the correct type from the literal (number, string, boolean) rather than emitting an untyped optional parameter. Co-Authored-By: Claude Sonnet 4.6 <noreply@anthropic.com>
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Summary
input1 = 123), the generated interface previously emitted an untyped optional (input1?), which provided no IntelliSense benefitnumber,string, orbooleanfrom numeric, string, and boolean literals respectively, producing correctly-typed optional parameters in the generated interfaceChanges
Chainableinterfacenumber,string,booleanTest plan
export function example(input1 = 123) {}→ generatesexample(input1?: number): Chainableexport function example(input1 = 'hello') {}→ generatesexample(input1?: string): Chainableexport function example(input1 = true) {}→ generatesexample(input1?: boolean): Chainableinput2: number = 0) is unchangedGenerated with Claude Code