Deserialize a T from a T ("identity" deserialization)?

[softwareCobbler]

I was wondering if it is possible to do the following (jackson3):

record Foo(...) {}
Map<String, Object> jsonMap = {"x" -> 42, "y" -> Foo, ...} // in the map, Foo is an actual Foo already
record Target(int x, Foo y, ...) {}
mapper.convertValue(jsonMap, Target.class)

Currently I get:
tools.jackson.databind.exc.MismatchedInputException: Cannot construct instance of Foo (although at least one Creator exists): cannot deserialize from Object value (no delegate- or property-based Creator)

I was hoping to configure the mapper to say something like "I need a T here, and I have a T here, so just return the T I have, no need to deserialize it". Is that possible?

[softwareCobbler]

Asked too soon, I see this works with a default constructor. But I guess I would still like to ask if it's possible even if the target type does NOT have a default constructor, to "just use the T it has already" rather than try to reconstruct (?) it.

[cowtowncoder]

It should work if I understand question correctly -- please file an issue with specific reproduction (ideally unit test) on jackson-databind. (along with usual things, version used).

And as least that'd show what I missed here if nothing else (wrt what exactly is desired).

[softwareCobbler]

I think I need to read some more, thank you for your time.

[cowtowncoder]

No problem, @softwareCobbler .