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added equal assignment operator Array<T>::operator=(ArrayView<T const> &) #266
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Just curious but is the
std::remove_constnecessary? I thought you don't have problems with duplicate const.Uh oh!
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I had put in
ArrayVIew<T>::operator=( ArrayView<T> const&),ArrayVIew<T>::operator=( ViewTypeConst const &), but then thought better of it. I felt it was a little unclear what the intent of the operator is, and whether it would be a source of bugs. I did put in thestd::remove_constbecause I was getting some errors in theusing, but now I am not sure I was this is what fixed the problem I was having. Also:https://stackoverflow.com/questions/5781222/duplicate-const-qualifier-allowed-in-c-but-not-in-c
but when I remove the
std::remove_constit compiles fine now. I could remove it, but I feel it is better to be explicit about it...not that this is valid reasoning.There was a problem hiding this comment.
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...but then again, if I do something like this:
it outputs:
So it is dropping the redundant const. If you dry to do:
you get:
so looks like it is illegal, but the compiler drops the second const when it is an alias??
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I think in http://eel.is/c++draft/dcl.type.cv#1 this sentence
refers to language grammar, i.e. what goes into text of a program, so it prohibits literally typing
const constanywhere. But thenThere was a problem hiding this comment.
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We rely on the shallow copy semantics of ArrayView in at least once place where we construct the element accessors. Plus it'd be weird to have the copy constructor do something so different from the assignment operator.