CoreTask#4: DualArray - Submit Your Code in Comment Section

[ErSKS]

CoreTask#4: DualArray - Define a Dual array to be an array where every value occurs exactly twice. For example, {1, 2, 1, 3, 3, 2} is a dual array. The following arrays are not Dual arrays {2, 5, 2, 5, 5} (5 occurs three times instead of two times) {3, 1, 1, 2, 2} (3 occurs once instead of two times) Write a function named isDual that returns 1 if its array argument is a Dual array. Otherwise it returns 0. Function signature is int isDual (int[ ] a)

[Niranjan2054]

package dualarray;

/**

• @author: Niranjan Bekoju

• @address: Liwali Bhaktapur

• @College: Khwopa College of Engineering
  */
  public class DualArray {

  public static void main(String[] args) {
  System.out.println("Is Dual {1, 4, 4, 3, 3, 5, 5, 1} 1:" + isDual(new int[]{1, 4, 4, 3, 3, 5, 5, 1}));
  System.out.println("Is Dual {1, 4, 4, 3, 9, 5, 5, 1} 0:" + isDual(new int[]{1, 4, 4, 3, 9, 5, 5, 1}));
  System.out.println("Is Dual {1, 4, 8, 3, 3, 5, 5} 0:" + isDual(new int[]{1, 4, 8, 3, 3, 5, 5}));
  System.out.println("Is Dual {1, 4, 3, 3, 3, 5, 5, 1} 0:" + isDual(new int[]{1, 4, 3, 3, 3, 5, 5, 1}));
  System.out.println("Is Dual {1, 4, 4, 9, 9, 5, 5, 1} 1:" + isDual(new int[]{1, 4, 4, 9, 9, 5, 5, 1}));
  System.out.println("Is Dual {1, 4, 4, 3, 3, 5, 5, 1} 1:" + isDual(new int[]{1, 4, 4, 3, 3, 5, 5, 1}));
  System.out.println("Is Dual {1, 4, 6, 3, 3, 6, 5, 1} 0:" + isDual(new int[]{1, 4, 6, 3, 3, 6, 5, 1}));
  System.out.println("Is Dual {1, 4, 4, 3, 3, 5, 5, 1} 1:" + isDual(new int[]{1, 4, 4, 3, 3, 5, 5, 1}));
  System.out.println("Is Dual {} 1:" + isDual(new int[]{}));
  }

  private static int isDual(int[] i) {
  int count = 0;
  if (i.length % 2 == 1) {
  return 0;
  }
  for (int j = 0; j < i.length; j++) {
  count = 0;
  for (int k = 0; k < i.length; k++) {
  if (i[j] == i[k]) {
  count++;
  }
  }
  if (count != 2) {
  return 0;
  }
  }
  return 1;
  }
  }

[tg199031]

CoreTask#4: DualArray - Define a Dual array to be an array where every value occurs exactly twice. For example, {1, 2, 1, 3, 3, 2} is a dual array. The following arrays are not Dual arrays {2, 5, 2, 5, 5} (5 occurs three times instead of two times) {3, 1, 1, 2, 2} (3 occurs once instead of two times) Write a function named isDual that returns 1 if its array argument is a Dual array. Otherwise it returns 0. Function signature is int isDual (int[ ] a)

[tg199031]

Dual array
Define a Dual array to be an array where every value occurs exactly twice. For example, {1, 2, 1, 3, 3, 2} is a dual array.The following arrays are not Dual arrays {2, 5, 2, 5, 5} (5 occurs three times instead of two times) {3, 1, 1, 2, 2} (3 occurs once instead of two times) Write a function named isDual that returns 1 if its array argument is a Dual array. Otherwise it returns 0.

[yosephhaile23]

Hi
How are you doing? I am good.
can you do it Dual array in JavaScript?
Thank you for your help.
Jos

[Abenezer-Baheru]

//Using JavaScript methods:
function isDual(arr){
if (arr.length % 2 !== 0) {
return 0;
} else{
let sortedArray = arr.sort((a, b) => a - b );
let evenIndex = arr.filter((value,i) => i %2 === 0)
let oddIndex = arr.filter((value,i) => i %2 !== 0)
let compare = evenIndex.map((value, i) => value == oddIndex[i])
if (compare.every((n) => n === true)){
return 1;
}
}
}
console.log(isDual([1, 2, 1, 3, 3, 2])) //output 1
console.log(isDual([2, 5, 2, 5, 5])) //output 0
console.log(isDual([3, 1, 1, 2, 2])) //putput 0

[danny-adev]

//Using JavaScript

let isDual = (array) => {
var count = 0;
if (array.length % 2 == 1) {
return 0;
}

for (j = 0; j < array.length; j++) {
count = 0;
for (k = 0; k < array.length; k++) {
if (array[j] == array[k]) {
count++;
}
}
if (count != 2) {
return 0;
}
}
return 1;
}

console.log(isDual([1, 2, 1, 3, 3, 2, 1, 1, 5, 6, 5, 6,])); //return 0 since it have more than 2 the same num

console.log(isDual([1, 2, 1, 3, 3, 2]));
console.log(isDual([2, 5, 2, 5, 5]));

console.log(isDual([3, 1, 1, 2, 2]));