Missing Test Case - 1. Two Sum

[mathanit]

LeetCode Username

mathanit

Problem Number, Title, and Link

1, two sum, https://leetcode.com/problems/two-sum/

Bug Category

Problem hints, Problem constraints

Bug Description

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

You can return the answer in any order.

Language Used for Code

Java

Code used for Submit/Run operation

class Solution {
    public int[] twoSum(int[] nums, int target) {
        int result[]=new int[2];
        int n=nums.length;
       
        for(int i=0;i<n;i++){
             int sum=0;
            for(int j=i;j<j+1;j++){
               sum=nums[j]+nums[j+1];
               if(sum==target){
                result[0]=j;
                result[1]=j+1;
                return result;
               }
              }     }
               return result;
    }
}

Expected behavior

Example 1:

Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:

Input: nums = [3,2,4], target = 6
Output: [1,2]
Example 3:

Input: nums = [3,3], target = 6
Output: [0,1]

Screenshots

No response

Additional context

No response

[exalate-issue-sync]

oj-leetcode commented: Hello mathanit,

Thank you for reaching out to us about the issue you're experiencing with the "Two Sum" problem on LeetCode. Based on your code submission, it seems there might be a misunderstanding regarding the implementation of the solution. The current logic checks only consecutive elements, which may lead to missing valid pairs since the two elements that sum to the target can be non-adjacent.

I recommend revisiting the logic to ensure that your solution considers all potential pairs within the array. You might find it helpful to refer to online resources or the LeetCode Discuss section for "Two Sum" where users discuss various approaches.

If you continue experiencing difficulties, please feel free to provide additional details or specific questions, and I'm here to assist you further.

Thank you for your understanding and cooperation.

LeetCode Support Team