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2 changes: 1 addition & 1 deletion content/computability/computability-theory/ce-sets.tex
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Expand Up @@ -15,7 +15,7 @@
\end{defn}

\begin{history}
Computably enumarable sets are also called \emph{recursively
Computably enumerable sets are also called \emph{recursively
enumerable} instead. This is the original terminology, and today
both are commonly used, as well as the abbreviations ``c.e.'' and
``r.e.''
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Expand Up @@ -9,7 +9,7 @@

\begin{editorial}
Material in this chapter should be reviewed and expanded. In
paticular, there are no exercises yet.
particular, there are no exercises yet.
\end{editorial}

\olimport{introduction}
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Expand Up @@ -155,7 +155,7 @@
string functions. In particular, suppose your programming language has
a function $\fn{diag}$ which works as follows: given an input
string~$s$, $\fn{diag}$ locates each instance of the symbol `x'
occuring in~$s$, and replaces it by a quoted version of the original
occurring in~$s$, and replaces it by a quoted version of the original
string. For example, given the string
\begin{quote}
\begin{verbatim}
Expand Down Expand Up @@ -189,7 +189,7 @@
\end{quote}
prints itself out $y$ times, on input $y$. Replacing the
$\fn{getinput}$---$\fn{print}$---$\fn{diag}$ skeleton by an
arbitrary funtion $g(x,y)$ yields
arbitrary function $g(x,y)$ yields
\begin{quote}
\begin{verbatim}
g(diag('g(diag(x), y)'), y)
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@@ -1,6 +1,6 @@
% Part: computability
% Chapter: recursive-functions
% Section: noations-pr-functions
% Section: notations-pr-functions

\documentclass[../../../include/open-logic-section]{subfiles}

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2 changes: 1 addition & 1 deletion content/counterfactuals/counterfactuals.tex
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@@ -1,4 +1,4 @@
% Part: conunterfactuals
% Part: counterfactuals

\documentclass[../../include/open-logic-part]{subfiles}

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world where I light the match and I do so in outer space is much
further removed from the actual world than the closest world where I
light the match is. So although it's true that the match lights in the
latter, it is not in the former. And that is as it schould be.
latter, it is not in the former. And that is as it should be.

\begin{ex}
The sphere semantics invalidates the inference, i.e., we have $p
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Expand Up @@ -14,7 +14,7 @@

\begin{explain}
Just as we've defined a number of important semantic notions
(\iftag{FOL}{validity}{tautology}, entailment, satisfiabilty), we now
(\iftag{FOL}{validity}{tautology}, entailment, satisfiability), we now
define corresponding \emph{proof-theoretic notions}. These are not
defined by appeal to satisfaction of !!{sentence}s in !!{structure}s,
but by appeal to the !!{derivability} or !!{nonderivability} of
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4 changes: 2 additions & 2 deletions content/first-order-logic/beyond/higher-order-logic.tex
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truth values, ``true'' and ``false,'' and a type $\Nat$ of natural
numbers. In that case, you can think of objects of type $\Nat \to
\Omega$ as unary relations, or subsets of $\Nat$; objects of type
$\Nat \to \Nat$ are functions from natural numers to natural numbers;
$\Nat \to \Nat$ are functions from natural numbers to natural numbers;
and objects of type $(\Nat \to \Nat) \to \Nat$ are ``functionals,''
that is, higher-type functions that take functions to numbers.

Expand Down Expand Up @@ -116,7 +116,7 @@
starting with $\Nat$, one can define real numbers, continuous
functions, and so on. It is also particularly attractive in the
context of intuitionistic logic, since the types have clear
``constructive'' intepretations. In fact, one can develop constructive
``constructive'' interpretations. In fact, one can develop constructive
versions of higher-type semantics (based on intuitionistic, rather
than classical logic) that clarify these constructive interpretations
quite nicely, and are, in many ways, more interesting than the
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4 changes: 2 additions & 2 deletions content/first-order-logic/beyond/intuitionistic-logic.tex
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\olsection{Intuitionistic Logic}

In constrast to second-order and higher-order logic, intuitionistic
In contrast to second-order and higher-order logic, intuitionistic
first-order logic represents a restriction of the classical version,
intended to model a more ``constructive'' kind of reasoning. The
following examples may serve to illustrate some of the underlying
Expand Down Expand Up @@ -180,7 +180,7 @@
To show that a sentence or propositional !!{formula} is intuitionistically
valid, all you have to do is provide a proof. But how can you show
that it is not valid? For that purpose, we need a semantics
that is sound, and preferrably complete. A semantics
that is sound, and preferably complete. A semantics
due to Kripke nicely fits the bill.

We can play the same game we did for classical logic: define the
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2 changes: 1 addition & 1 deletion content/first-order-logic/beyond/second-order-logic.tex
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Expand Up @@ -114,7 +114,7 @@
full !!{structure}s only.
\end{enumerate}
When logicians do not specify the !!{derivation} system or the semantics they
have in mind, they are usually refering to the second item on each
have in mind, they are usually referring to the second item on each
list. The advantage to using this semantics is that, as we will see,
it gives us categorical descriptions of many natural mathematical
structures; at the same time, the !!{derivation} system is quite strong, and
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2 changes: 1 addition & 1 deletion content/first-order-logic/completeness/compactness.tex
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Expand Up @@ -108,7 +108,7 @@
terms. Let $a \in \Domain{M}$ be !!a{element} of $\Domain{M}$ not
picked out by any of them, and let $\Struct{M'}$ be the !!{structure}
that is just like $\Struct{M}$, but also $\Assign{c}{M'} = a$. Since
$a \neq \Value{t}{M}$ for all~$t$ occuring in~$\Delta'$,
$a \neq \Value{t}{M}$ for all~$t$ occurring in~$\Delta'$,
$\Sat{M'}{\Delta'}$. Since $\Sat{M}{\Gamma}$, $\Gamma' \subseteq
\Gamma$, and $c$ does not occur in~$\Gamma$, also
$\Sat{M'}{\Gamma'}$. Together, $\Sat{M'}{\Gamma' \cup \Delta'}$ for
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2 changes: 1 addition & 1 deletion content/first-order-logic/completeness/downward-ls.tex
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\begin{proof}
If $\Gamma$ is consistent and contains no sentences in which identity
appears, then the !!{structure}~$\Struct M$ delivered by the proof of
the completness theorem has a domain $\Domain{M}$ identical to the set
the completeness theorem has a domain $\Domain{M}$ identical to the set
of terms of the language~$\Lang L'$. So $\Struct{M}$ is
!!{denumerable}, since $\Trm[L']$ is.
\end{proof}
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% Section: maximally-consistent-sets

% Definition of maximally consistent sets. Properties of mcs required
% for completeness proved are in maximally-consistsnt-sets.tex in the
% for completeness proved are in maximally-consistent-sets.tex in the
% chapter on the proof system used.

\documentclass[../../../include/open-logic-section]{subfiles}
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!!{sentence}~$!A$ as its last formula (and $\Gamma$ is taken as the
set of !!{sentence}s in that derivation which are justified by~(2) above). $!A$
is a theorem if~$!A$ has !!a{derivation} where~$\Gamma$ is empty,
i.e., every !!{sentence} in the derivation is justfied either by (1)
i.e., every !!{sentence} in the derivation is justified either by (1)
or~(3). For instance, here is !!a{derivation} that shows that $\Proves
!A \lif (!B \lif (!B \lor !A))$:
\begin{derivation}
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4 changes: 2 additions & 2 deletions content/incompleteness/introduction/definitions.tex
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framework, and a system of axioms. For our purposes, let us suppose
that mathematics can be formalized in a first-order language, i.e.,
that there is some set of !!{constant}s, !!{function}s, and
!!{predicate}s which, together with the connectives and quatifiers of
!!{predicate}s which, together with the connectives and quantifiers of
first-order logic, allow us to express the claims of mathematics.
Most people agree that such a language exists: the language of set
theory, in which $\in$ is the only non-logical symbol. That such a
Expand Down Expand Up @@ -223,7 +223,7 @@
$y_1$, \dots, $y_n$ are all the free variables of~$!A$ and the initial
quantifiers of~$!B$ bind the variables~$y_1$, \dots,~$y_n$. Once we
have extracted this~$!A$ and checked that its free variables match the
variables bound by the universal qauntifiers at the front
variables bound by the universal quantifiers at the front
and~$\lforall[x]$, we go on to check that the antecedent of the
conditional matches
\[
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Expand Up @@ -209,7 +209,7 @@
This struck a lethal blow to Hilbert's original program. However, as
is so often the case in mathematics, it also opened up exciting new
avenues for research. If there is no one, all-encompassing formal
system of mathematics, it makes sense to develop more circumscribesd
system of mathematics, it makes sense to develop more circumscribed
systems and investigate what can be proved in them. It also makes
sense to develop less restricted methods of proof for establishing the
consistency of these systems, and to find ways to measure how hard it
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2 changes: 1 addition & 1 deletion content/incompleteness/introduction/overview.tex
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their own consistency statements. The conditions required for this
theorem to apply are a bit more stringent than just that the theory
represents all computable functions and !!{decidable} relations, but
we will show that $\Th{PA}$ satisifes them.
we will show that $\Th{PA}$ satisfies them.

\end{document}
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Expand Up @@ -8,7 +8,7 @@

\olfileid{inc}{tcp}{itp}

\olsection{Theories in which $\Th{Q}$ is Intepretable are Undecidable}
\olsection{Theories in which $\Th{Q}$ is Interpretable are Undecidable}

We can strengthen these results even more. Informally, an
interpretation of a language $\Lang{L_1}$ in another language
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Expand Up @@ -246,7 +246,7 @@ \subsection{Examples of \usetoken{P}{derivation}}
\end{proof}

\begin{prob}
Give !!{derivation}s in intutionistic logic of the following !!{formulas}:
Give !!{derivation}s in intuitionistic logic of the following !!{formulas}:
\begin{enumerate}
\item $(\lnot !A \lor !B) \lif (!A \lif !B)$
\item $\lnot\lnot\lnot !A \lif \lnot !A$
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Expand Up @@ -12,7 +12,7 @@
Curry-Howard correspondence. It needs more explanation and
motivation, and there are probably errors and omissions. The proof
of normalization should be reviewed and expanded. There are no
examples for the product type. Permuation and simplification
examples for the product type. Permutation and simplification
conversions are not covered. It will make a lot more sense once
there is also material on the (typed) lambda calculus which is
basically presupposed here. Use with extreme caution.
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Expand Up @@ -141,7 +141,7 @@
lambda calculus as if we are dealing with untyped terms.

Finally, the reduction of the function type corresponds to removal of
a detour of a $\Intro\lif$ followd by a $\Elim\lif$.
a detour of a $\Intro\lif$ followed by a $\Elim\lif$.
\begin{gather*}
\bottomAlignProof
\AxiomC{$\Discharge{!A}{u}$}
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2 changes: 1 addition & 1 deletion content/intuitionistic-logic/semantics/propositions.tex
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@@ -1,6 +1,6 @@
% part: intuitionistic-logic
% chapter: semantics
% section: propositionas
% section: propositions

\documentclass[../../../include/open-logic-section]{subfiles}

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@@ -1,5 +1,5 @@
% part: intuitionistic-logic
% chapter: soundeness-completeness
% chapter: soundness-completeness
% section: canonical-model

\documentclass[../../../include/open-logic-section]{subfiles}
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@@ -1,5 +1,5 @@
% part: intuitionistic-logic
% chapter: soundeness-completeness
% chapter: soundness-completeness
% section: completeness-thm

\documentclass[../../../include/open-logic-section]{subfiles}
Expand Down Expand Up @@ -36,7 +36,7 @@
\begin{prob}
By using the completeness theorem prove that if $\Proves !A \lor !B$ then
$\Proves !A$ or $\Proves !B$. (Hint: Assume $\mSat/{M_1}{!A}$ and
$\mSat/{M_2}{!B}$ and contruct a new model $\mModel{M}$ such that
$\mSat/{M_2}{!B}$ and construct a new model $\mModel{M}$ such that
$\mSat/{M}{!A \lor !B}$.)
\end{prob}

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@@ -1,5 +1,5 @@
% part: intuitionistic-logic
% chapter: soundeness-completeness
% chapter: soundness-completeness
% section: decidability

\documentclass[../../../include/open-logic-section]{subfiles}
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@@ -1,5 +1,5 @@
% part: intuitionistic-logic
% chapter: soundeness-completeness
% chapter: soundness-completeness
% section: lindenbaum

\documentclass[../../../include/open-logic-section]{subfiles}
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Expand Up @@ -11,7 +11,7 @@
This chapter collects soundness and completeness results for
propositional intuitionistic logic. It needs an introduction. The
completeness proof makes use of facts about provability that should
be stated and proved explicitly somehwere.
be stated and proved explicitly somewhere.
\end{editorial}

\olimport{soundness-axd}
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2 changes: 1 addition & 1 deletion content/methods/induction/introduction.tex
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Expand Up @@ -18,7 +18,7 @@
inference from the particular to the general. For instance, if we
observe many green emeralds, and nothing that we would call an emerald
that's not green, we might conclude that all emeralds are green. This
is an inductive inference, in that it proceeds from many particlar
is an inductive inference, in that it proceeds from many particular
cases (this emerald is green, that emerald is green, etc.) to a
general claim (all emeralds are green). \emph{Mathematical} induction
is also an inference that concludes a general claim, but it is of a
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4 changes: 2 additions & 2 deletions content/methods/methods.tex
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\begin{editorial}
This part covers general and methodological material, especially
explanations of various proof methods a non-methematics student may
explanations of various proof methods a non-mathematics student may
be unfamiliar with. It currently contains a chapter on how to write
proofs, and a chapter on induction, but additional sections for
thos, exercises, and a chapter on mathematical terminology is also
those, exercises, and a chapter on mathematical terminology is also
planned.
\end{editorial}

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2 changes: 1 addition & 1 deletion content/methods/proofs/reading-proofs.tex
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Expand Up @@ -45,7 +45,7 @@
\subseteq A$.''
\end{quote}

This is the first half of the proof of the identity: it estabishes
This is the first half of the proof of the identity: it establishes
that if an arbitrary~$z$ is !!a{element} of the left side, it is also
!!a{element} of the right, i.e., $A \cap (A \cup B) \subseteq A$.
Assume that $z \in A \cap (A \cup B)$. Since $z$ is an !!{element} of
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2 changes: 1 addition & 1 deletion content/methods/proofs/using-definitions.tex
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Expand Up @@ -102,7 +102,7 @@

\begin{prob}
Suppose you are asked to prove that $A \cap B \neq \emptyset$. Unpack
all the definitions occuring here, i.e., restate this in a way that
all the definitions occurring here, i.e., restate this in a way that
does not mention ``$\cap$'', ``='', or ``$\emptyset$''.
\end{prob}

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4 changes: 2 additions & 2 deletions content/model-theory/basics/dlo.tex
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Expand Up @@ -11,7 +11,7 @@ \section{Dense Linear Orders}

\begin{defn}
A \emph{dense linear ordering without endpoints} is !!a{structure}
$\Struct{M}$ for the !!{language} containg a single 2-place
$\Struct{M}$ for the !!{language} containing a single 2-place
!!{predicate}~$<$ satisfying the following sentences:
\begin{enumerate}
\item $\lforall[x][\lnot x < x]$;
Expand Down Expand Up @@ -39,7 +39,7 @@ \section{Dense Linear Orders}
Back-and-Forth property. Then $\Struct{M_1} \iso[p] \Struct{M_2}$,
and the theorem follows by \olref[pis]{thm:p-isom1}.

To show $\PIso{I}$ satisifes the Forth property, let $p \in
To show $\PIso{I}$ satisfies the Forth property, let $p \in
\PIso{I}$ and let $p(a_i) = b_i$ for $i = 1$, \dots,~$n$, and
without loss of generality suppose $a_1 <_1 a_2 <_1 \cdots <_1
a_n$. Given $a \in \Domain{M_1}$, find $b \in \Domain{M_2}$ as
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2 changes: 1 addition & 1 deletion content/model-theory/models-of-arithmetic/introduction.tex
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Expand Up @@ -13,7 +13,7 @@ \section{Introduction}
!!{structure}~$\Struct{N}$ with $\Domain{N} = \Nat$ in which
$\Obj{0}$, $\prime$, $+$, $\times$, and $<$ are interpreted as you
would expect. That is, $\Obj{0}$ is $0$, $\prime$ is the successor
function, $+$ is interpeted as addition and $\times$ as multiplication
function, $+$ is interpreted as addition and $\times$ as multiplication
of the numbers in~$\Nat$. Specifically,
\begin{align*}
\Assign{\Obj{0}}{N} & = 0\\
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4 changes: 2 additions & 2 deletions content/model-theory/models-of-arithmetic/models-of-q.tex
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Expand Up @@ -120,7 +120,7 @@ \section{Models of $\Th{Q}$}

\begin{prob}
Prove that $\Struct{K}$ from \olref[mod][mar][mdq]{ex:model-K-of-Q}
satisifies the remaining axioms of~$\Th{Q}$,
satisfies the remaining axioms of~$\Th{Q}$,
\begin{align*}
& \lforall[x][\eq[(x \times \Obj 0)][\Obj 0]] \tag{$!Q_6$}\\
& \lforall[x][\lforall[y][\eq[(x \times y')][((x \times y) + x)]]] \tag{$!Q_7$}\\
Expand Down Expand Up @@ -176,7 +176,7 @@ \section{Models of $\Th{Q}$}
\begin{prob}
Expand $\Struct{L}$ of \olref[mod][mar][mdq]{ex:model-L-of-Q} to
include $\nstimes$ and $\nsless$ that interpret~$\times$ and $<$. Show
that your structure satisifies the remaining axioms of~$\Th{Q}$,
that your structure satisfies the remaining axioms of~$\Th{Q}$,
\begin{align*}
& \lforall[x][\eq[(x \times \Obj 0)][\Obj 0]] \tag{$!Q_6$}\\ &
\lforall[x][\lforall[y][\eq[(x \times y')][((x \times y) + x)]]]
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Expand Up @@ -85,7 +85,7 @@
\ollabel{fig:ser-eucl2}
\end{figure}

In particular, to obtain a euclidean flitration it is not enough to
In particular, to obtain a euclidean filtration it is not enough to
consider filtrations through arbitrary $\Gamma$'s closed under
sub-!!{formula}s. Instead we need to consider sets $\Gamma$ that are
\emph{modally closed} (see \olref[pre]{defn:modallyclosed}). Such sets
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2 changes: 1 addition & 1 deletion content/normal-modal-logic/tableaux/introduction.tex
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Expand Up @@ -25,7 +25,7 @@
applied. When a branch contains both $\sFmla{\True}{!A}$ and
$\sFmla{\False}{!A}$, we say the branch is \emph{closed}. If every
branch in !!a{tableau} is closed, the entire !!{tableau} is closed. A
closed !!{tableau} consititues !!a{derivation} that shows that the set
closed !!{tableau} constitutes !!a{derivation} that shows that the set
of !!{signed formula}s which were used to begin the !!{tableau} are
unsatisfiable. This can be used to define a $\Proves$ relation:
$\Gamma \Proves !A$ iff there is some finite set~$\Gamma_0 = \{!B_1,
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2 changes: 1 addition & 1 deletion content/reference/reference.tex
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@@ -1,4 +1,4 @@
% Part: refeence
% Part: reference

\documentclass[../../include/open-logic-part]{subfiles}

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Expand Up @@ -13,7 +13,7 @@
\begin{explain}
The (Downward) L\"owenheim-Skolem Theorem states that every set of
!!{sentence}s with an infinite model has !!a{enumerable} model. It,
too, is a consequence of the completeneness theorem: the proof of
too, is a consequence of the completeness theorem: the proof of
completeness generates a model for any consistent set of
!!{sentence}s, and that model is !!{enumerable}. There is also an
Upward L\"owenheim-Skolem Theorem, which guarantees that if a set of
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