result of ^^ is not the last evaluated expression.

[briandfoy]

The ^^ operator can't return the last evaluated expression since it could either be true or false, and would not indicate the success of the XOR. You can see this by using ^^:

$ perl -E 'say q(A) ^^ q(B)'

$ perl -E 'say q(0) ^^ q(B)'
1

• This set of changes does not require a perldelta entry.

The docs may need further revisions to distinguish ^^ from the other logical operators. I think the re-organization of the separate sections for ||, //, and ^^ was a mistake that will cause more confusion for people since these three are dissimilar enough to need sections that distinguish them sufficiently.

[Grinnz]

There are several examples of that with operators that are the same precedence. Redesigning perlop may be useful but would be a larger task. Selfishly, I would like a redesign that makes it easier to give them searchable operator-pages on perldoc.perl.org. But I think that would be better served as a new document or section, or a module similar to Pod::Functions.

[Grinnz]

Ref #23224

[book]

^^ is also the only one that can't short-circuit.

Which made me think (and double-check) that && does return the last evaluated expression:

$ perl -E 'say $_ && 2 for 0, "", 3'
0

2