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Expand Up @@ -324,7 +324,7 @@ public class Solution {
**进阶——一次遍历法:**


> **链表中倒数第N个节点也就是正数第(L-N+1)个节点。
> 链表中倒数第N个节点也就是正数第(L-N+1)个节点。

其实这种方法就和我们上面第四题找“链表中倒数第k个节点”所用的思想是一样的。**基本思路就是:** 定义两个节点 node1、node2;node1 节点先跑,node1节点 跑到第 n+1 个节点的时候,node2 节点开始跑.当node1 节点跑到最后一个节点时,node2 节点所在的位置就是第 (L-n ) 个节点(L代表总链表长度,也就是倒数第 n+1 个节点)

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