Impossible to pass multiple arguments to mutation function in useMutation hook

[CedricVanhaverbeke]

Describe the bug
I cannot seem to pass mutliple arguments to a function created with the useMutation hook.

To Reproduce

// create a mutation
const [mutation] = useMutation((...elements) => console.log(elements));

// execute the mutation with multiple parameters
mutation(1,2,3);

// output is this:
[1]

Expected behavior
I'd expect the full array of arguments like this:

[1,2,3]

Am I missing something?

[ghostd]

Hi,

As you can see in the documentation and in the TypeScript definitions the mutation function only accepts an object as parameter.

So you can do this:

const [mutation] = useMutation(({data: elements}) => console.log(elements));
mutation({data: [1,2,3]});

[TkDodo]

Here is a discussion about that topic: #1226

[tannerlinsley]

We'll keep talking about it in #1226, but for now, the current design will stick around.

[HarryShindika]

I placed my values in an array then passed the array to mutate(). This worked