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When attempting to parse swagger document, parser.scala is using the path to try to match against existing models. This is resulting in the following exception:
java.lang.RuntimeException: Could not find model at url[/inventory/product/{product_code}]
at scala.sys.package$.error(package.scala:27)
at me.apidoc.swagger.Parser$$anonfun$resources$1.apply(Parser.scala:129)
at me.apidoc.swagger.Parser$$anonfun$resources$1.apply(Parser.scala:125)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:245)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:245)
at scala.collection.Iterator$class.foreach(Iterator.scala:750)
at scala.collection.AbstractIterator.foreach(Iterator.scala:1202)
at scala.collection.IterableLike$class.foreach(IterableLike.scala:72)
at scala.collection.AbstractIterable.foreach(Iterable.scala:54)
at scala.collection.TraversableLike$class.map(TraversableLike.scala:245)
at scala.collection.AbstractTraversable.map(Traversable.scala:104)
at me.apidoc.swagger.Parser.resources(Parser.scala:125)
at me.apidoc.swagger.Parser.parse(Parser.scala:51)
at me.apidoc.swagger.Parser.parseString(Parser.scala:19)
at me.apidoc.swagger.SwaggerServiceValidator$$anonfun$1.apply(SwaggerServiceValidator.scala:13)
at me.apidoc.swagger.SwaggerServiceValidator$$anonfun$1.apply(SwaggerServiceValidator.scala:13)
We can use the schema object to get the reference to the model instead.
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