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34 changes: 34 additions & 0 deletions Arrays/MergeIntervals.java
Original file line number Diff line number Diff line change
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/* Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.



Example 1:

Input: intervals = [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6].
Example 2:

Input: intervals = [[1,4],[4,5]]
Output: [[1,5]]
Explanation: Intervals [1,4] and [4,5] are considered overlapping. */

public class MergeIntervals{

public int[][] merge(int[][] intervals) {
LinkedList<int[]> mergedList = new LinkedList<>();

for(int[] interval : intervals){
if(mergedList.isEmpty() || mergedList.getLast()[1] < interval[0]){
mergedList.add(interval);
} else {
int[] lastInterval = mergedList.getLast();
lastInterval[1] = Math.max(lastInterval[1], interval[1]);
mergedList.removeLast();
mergedList.add(lastInterval);
}
}
return mergedList.toArray(new int[mergedList.size()][]);
}

}