how do i get endpoint like flask by request.endpoint

[un-human]

question

• fastapi, how do i get endpoint; like flask by request.endpoint ??

[ycd]

There is a similar request object.

async def dummy(request: Request):
    return request.url.path

[un-human]

There is a similar request object.

async def dummy(request: Request):
    return request.url.path

request.url.path Not what I wanted；
i wanted the router_name and the function_name , like flask

[ycd]

Hmm you mean something like this

from starlette.routing import Match

routes = request.app.router.routes
for route in routes:
    match, scope = route.matches(request)
    if match == Match.FULL:
        path = route.path

[un-human]

Hmm you mean something like this

from starlette.routing import Match

routes = request.app.router.routes
for route in routes:
    match, scope = route.matches(request)
    if match == Match.FULL:
        path = route.path

from fastapi import APIRouter, FastAPI
app = FastAPI()
router = APIRouter(prefix='/user')

@router.get("/route/{id}")
async def route_time(id: int,request: Request):
    # here,i want get the  "user" of router   and “route_time” of the function_name , not "/route/{id}" of url_path
    pass

[ycd]

I assume it worked.

[tiangolo]

Thanks for the help here @ycd ! 👏 🙇

Thanks for coming back and closing the issue @stringk245 👍

Sorry for the long delay! 🙈 I wanted to personally address each issue/PR and they piled up through time, but now I'm checking each one in order.