non-intuitive output directory

[aryzing]

What version of protobuf and what language are you using?
Version: libprotoc 3.8.0, Go

What did you do?
protoc api/service.proto --go_out=plugins=grpc:api

What did you expect to see?
For the output to be in the destination folder api (as specified by the args to --go_out)

What did you see instead?
The output was put inside api/api directory (it created a directory named api inside api. To get the desired results, I need to specify my target directory as .. which is totally counter-intuitive.

I'm aware of the paths flag, and i was looking for a paths=cwd or similar where I can actually specify the output directory based on where I'm running the command from.

[neild]

protoc api/service.proto --go_out=plugins=grpc,paths=source_relative:. probably does what you want (puts the output in api/service.pb.go).

The paths=source_relative option causes the output for path/to/some.proto to be path/to/some.pb.go. Setting the output directory to . (the current directory) will cause every .pb.go file to be generated alongside the corresponding .proto file.