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‎1.Introduction to Python.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Find average Marks"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"<br><b>Write a program to input marks of three tests of a student (all integers). Then calculate and print the average of all test marks.</b>\n",
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"<br><b>Input format :</b>\n",
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"<br>3 Test marks (in different lines)\n",
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"<br><b>Output format :</b>\n",
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"<br>Average\n",
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"<br><b>Sample Input 1 :</b>\n",
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"<br>3\n",
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"<br>4 \n",
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"<br>6\n",
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"<br><b>Sample Output 1 :</b>\n",
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"<br>4.333333333333333\n",
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"<br><b>Sample Input 2 :</b>\n",
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"<br>5 \n",
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"<br>10 \n",
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"<br>5\n",
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"<br><b>Sample Output 2 :</b>\n",
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"<br>6.666666666666667"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"sub_1=int(input(\"\"))\n",
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"sub_2=int(input(\"\"))\n",
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"sub_3=int(input(\"\"))\n",
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"Average_of_3_subjects=(sub_1+sub_2+sub_3)\n",
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"print(Average_of_3_subjects/3)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Find X raised to power N"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"<br><b>You are given two integers: X and N. You have to calculate X raised to power N and print it.</b>\n",
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"<br><b>Input format:</b>\n",
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"<br>The first line of input contains an integer X (1 <= X <= 100)\n",
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"<br>The second line of input contains an integer N (1 <= N <= 10) \n",
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"<br><b>Constraints:</b>\n",
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"<br>Time Limit: 1 second\n",
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"<br><b>Output format:</b>\n",
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"<br>The first and only line of output contains the result. \n",
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"<br><b>Sample Input:</b>\n",
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"<br>10\n",
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"<br>4\n",
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"<br><b>Sample Output:</b>\n",
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"<br>10000"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"X=int(input())\n",
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"N=int(input())\n",
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"\n",
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"print(X**N)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Arithmetic Progression"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"<br><b>You are given first three entries of an arithmetic progression. You have to calculate the common difference and print it.</b>\n",
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"<br><b>Input format:</b>\n",
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"<br>The first line of input contains an integer a (1 <= a <= 100)\n",
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"<br>The second line of input contains an integer b (1 <= b <= 100) \n",
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"<br>The third line of input contains an integer c (1 <= c <= 100) \n",
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"<br><b>Constraints:</b>\n",
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"<br>Time Limit: 1 second\n",
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"<br><b>Output format:</b>\n",
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"<br>The first and only line of output contains the result. \n",
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"<br><b>Sample Input:</b>\n",
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"<br>1\n",
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"<br>3\n",
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"<br>5\n",
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"<br><b>Sample Output:</b>\n",
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"<br>2"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"a=int(input())\n",
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"b=int(input())\n",
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"c=int(input())\n",
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"print(b-a)\n"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Rectangular Area"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"<br><b>You are given a rectangle in a plane. The corner coordinates of this rectangle is provided to you. You have to print the amount of area of the plane covered by this rectangles.</b>\n",
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"<br>The end coordinates are provided as four integral values: x1, y1, x2, y2. It is given that x1 < x2 and y1 < y2.\n",
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"<br><b>Input format:</b>\n",
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"<br>The first line of input contains an integer x1 (1 <= x1 <= 10)\n",
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"<br>The second line of input contains an integer y1 (1 <= y1 <= 10) \n",
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"<br>The third line of input contains an integer x2 (1 <= x2 <= 10)\n",
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"<br>The fourth line of input contains an integer y2 (1 <= y2 <= 10) \n",
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"<br><b>Constraints:</b>\n",
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"<br>Time Limit: 1 second\n",
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"<br><b>Output format:</b>\n",
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"<br>The first and only line of output contains the result.\n",
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"<br><b>Sample Input:</b>\n",
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"<br>1\n",
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"<br>1\n",
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"<br>3\n",
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"<br>3\n",
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"<br><b>Sample Output:</b>\n",
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"<br><br>4"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"x1=int(input())\n",
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"y1=int(input())\n",
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"x2=int(input())\n",
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"y2=int(input())\n",
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"print((x2-x1)*(y2 - y1))"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

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