TypeError: gulp.files is not a function

[StephenBugden]

Hello,

I am trying to run the code below to validate some css and write the results to a file. I took the code from and modified it to use my directories:
https://www.npmjs.com/package/gulp-csslint

I'm getting an error with the following message:
TypeError: gulp.files is not a function

Here's the code:
//************************************************
var gulp = require('gulp');

var CSS_PATH = 'public/css/*/.css';
var DIST_PATH = 'public/dist';

gulp.task('lintcss', function(cb) {
  var fs = require('fs');
  var output = '';
 
gulp.files(CSS_PATH)
.pipe(csslint())
    .pipe(csslint.reporter('junit-xml', {logger: function(str) { output += str; }}));
 
  fs.writeFile(DIST_PATH + 'junit.xml', output, cb);
});
//*****************************************************

Best Regards,

Steve

[lazd]

The docs seem to have an error, it should be gulp.src, not gulp.files. I've updated the docs, thanks!

[StephenBugden]

Hi Larry,

Thank you for your reply.

I tried all sorts of things, that was one of them it just gives me a blank
file even though I put errors in my css. There must be something else that
needs to change.

Steve

On 3 May 2016 at 21:15, Larry Davis notifications@github.com wrote:

The docs seem to have an error, it should be gulp.src, not gulp.files.
I've updated the docs, thanks!

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