`AudioFrame` with a small rate can result in a size of zero

[microbit-carlos]

>>> len(AudioFrame(1000, 1))
32
>>> len(AudioFrame(999, 1))
0
>>> len(AudioFrame(1, 1))
0
>>> 

Likely the integer division flooring (well, rounding towards zero) from:

micropython-microbit-v2/src/codal_port/modaudio.c

Line 334 in c91ae4e

size = args[ARG_duration].u_int * rate / 1000;

[dpgeorge]

I have changed the code to ensure that the size is always at least 32 bytes.

[microbit-carlos]

Great, thanks Damien!

[microbit-carlos]

I have changed the code to ensure that the size is always at least 32 bytes.

Using a small duration or rate can still create an AudioFrame with less than 32 bytes:

>>> len(AudioFrame(1000, 1))
1
>>> len(AudioFrame(1, 1))
1
>>> 

[dpgeorge]

Using a small duration or rate can still create an AudioFrame with less than 32 bytes:

This is intended.

Now that the code supports arbitrary byte lengths (ie no longer a multiple of 32), it's possible to create frames all the way down to 1 byte in size.

[microbit-carlos]

Sounds good, thanks Damien!