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Description
Thank you for writing and maintaining plotly!
When making a scatterplot, I like to specify pch = 21 to print an outline around points. This helps distinguish points when they are close together. When I use this plotting scheme, ggplot2 gives the expected output, but plotly ignores the aesthetics supplied by scale_fill_gradient2() and gives the error number of items to replace is not a multiple of replacement length. I believe this issue is similar to #1149.
# R v4.0.5
library(plotly) # v 4.9.4.1
library(ggplot2) # v 3.3.3
p <- ggplot(data = wdat, mapping = aes(x = Age, y = as.numeric(ABV))) +
geom_jitter(mapping = aes(fill = Score), size = 2.5, pch = 21) +
scale_fill_gradient2(low = "#0008ff",
midpoint = mean(wdat$Score),
mid = "purple",
high = "#ff0000") +
scale_y_continuous(name = "% ABV",
limits = c(40, 70),
breaks = seq(from = 40, 70, 5)) +
theme_classic()
p + ggtitle("ggplot2")
ggplotly(p + ggtitle("plotly"))
If I switch my mapping aesthetic to color with pch = 19 and specify a gradient with scale_color_gradient2(), then ggplot2 and plotly give the same output without error. However, the desired outlines are lost.
p <- ggplot(data = wdat, mapping = aes(x = Age, y = as.numeric(ABV))) +
geom_jitter(mapping = aes(color = Score), size = 2.5, pch = 19) +
scale_color_gradient2(low = "#0008ff",
midpoint = mean(wdat$Score),
mid = "purple",
high = "#ff0000") +
scale_y_continuous(name = "% ABV",
limits = c(40, 70),
breaks = seq(from = 40, 70, 5)) +
theme_classic()
p + ggtitle("ggplot2")
ggplotly(p + ggtitle("plotly"))
Here is my scheme for downloading the dataset, in case you want to troubleshoot with the same data:
library(dplyr) # v 1.0.5
library(gsheet) # v 0.4.5
url <- "https://docs.google.com/spreadsheets/d/1geSFmGKWhoSzoSblQQK6fDzWSujY-MQ9w2b3VNbTxZk"
wdat <- gsheet::construct_download_url(url = url) %>%
gsheet::gsheet2tbl(url = .) %>%
mutate(ABV = gsub("%","",ABV) %>%
as.numeric() %>%
round(., 3) %>%
format(., nsmall = 1)) %>%
na.omit()



