assert helper to compare list contents, ignoring order

[soxofaan]

I created this small pytest assert helper to compare lists/tuples ignoring item order:
https://gist.github.com/soxofaan/8e6512f765f0f0df697311c2561be57e

It's roughly assert sorted(actual) == sorted(expected), but with some added benefits:

• container type (list vs tuple) is also checked
• inspired by pytest.approx, to make it more explicit what the intention of the comparison is. You only have to use it in the expected object, you can leave the actual object as is. It also works inside nested structures, e.g.

  assert {"foo": [1, 2, 3]} == {"foo": IgnoreOrder([3, 2, 1])}
  

Would it be worthwhile to create a PR for this?

[nicoddemus]

I like the idea; often one goes and uses a sorted() call, but that's not ideal because as you mention, it doesn't check the container type. Also using it inside nested structures is a plus.

Now to bike shedding. 😁

What should we call it? pytest.anyorder?

What others think?

[asottile]

I believe this is a duplicate of #5548

[nicoddemus]

Ahh indeed, we discussed this before and pytest-unordered was created because of that, although I'm not sure pytest-unordered also checks the types of the sequences being compared...

[soxofaan]

thanks for the reference

closing this one