add output for max_product algorithm

Author: vbrazo

data_structures/arrays/maximum_product_subarray.rb

@@ -1,44 +1,51 @@
-#Given an integer array nums, find a contiguous non-empty subarray within the array that has the largest product, and return the product.
-#It is guaranteed that the answer will fit in a 32-bit integer.
-#A subarray is a contiguous subsequence of the array.
-
-#Example 1:
-#Input: nums = [2,3,-2,4]
-#Output: 6
-#Explanation: [2,3] has the largest product 6.
-
-#Example 2:
-#Input: nums = [-2,0,-1]
-#Output: 0
-#Explanation: The result cannot be 2, because [-2,-1] is not a subarray.
-
-#Constraints:
-#1 <= nums.length <= 2 * 104
-#-10 <= nums[i] <= 10
-#The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.
 
+# Given an integer array nums, find a contiguous non-empty subarray within the array that has the largest product, and return the product.
+# It is guaranteed that the answer will fit in a 32-bit integer.
+# A subarray is a contiguous subsequence of the array.
 
+# Example 1:
+# Input: nums = [2,3,-2,4]
+# Output: 6
+# Explanation: [2,3] has the largest product 6.
 
+# Example 2:
+# Input: nums = [-2,0,-1]
+# Output: 0
+# Explanation: The result cannot be 2, because [-2,-1] is not a subarray.
 
-#Dynamic Programming Approach (Kadane's Algorithm) - O(n) Time / O(1) Space
-#Track both current minimum and current maximum (Due to possibility of multiple negative numbers)
-#Answer is the highest value of current maximum
+# Constraints:
+# 1 <= nums.length <= 2 * 104
+#-10 <= nums[i] <= 10
+# The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.
 
+# Dynamic Programming Approach (Kadane's Algorithm) - O(n) Time / O(1) Space
+# Track both current minimum and current maximum (Due to possibility of multiple negative numbers)
+# Answer is the highest value of current maximum
 
 # @param {Integer[]} nums
 # @return {Integer}
 def max_product(nums)
-    return nums[0] if nums.length == 1
-    
-    cur_min, cur_max, max = 1, 1, -11
-    
-    nums.each do |val|
-      tmp_cur_max = cur_max
-      cur_max = [val, val*cur_max, val*cur_min].max
-      cur_min = [val, val*tmp_cur_max, val*cur_min].min
-      
-      max = [max, cur_max].max
-    end
-    
-    max
-end
+  return nums[0] if nums.length == 1
+
+  cur_min = 1
+  cur_max = 1
+  max = -11
+
+  nums.each do |val|
+    tmp_cur_max = cur_max
+    cur_max = [val, val * cur_max, val * cur_min].max
+    cur_min = [val, val * tmp_cur_max, val * cur_min].min
+
+    max = [max, cur_max].max
+  end
+
+  max
+end
+
+nums = [2, 3, -2, 4]
+puts max_product(nums)
+# Output: 6
+
+nums = [-2, 0, -1]
+puts max_product(nums)
+# Output: 0