Add solution and test-cases for problem 2914

leetcode/2901-3000/2914.Minimum-Number-of-Changes-to-Make-Binary-String-Beautiful/README.md

@@ -1,28 +1,44 @@
 # [2914.Minimum Number of Changes to Make Binary String Beautiful][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+You are given a **0-indexed** binary string `s` having an even length.
+
+A string is **beautiful** if it's possible to partition it into one or more substrings such that:
+
+- Each substring has an **even length**.
+- Each substring contains **only** `1`'s or **only** `0`'s.
+
+You can change any character in `s` to `0` or `1`.
+
+Return the **minimum** number of changes required to make the string `s` beautiful.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: s = "1001"
+Output: 2
+Explanation: We change s[1] to 1 and s[3] to 0 to get string "1100".
+It can be seen that the string "1100" is beautiful because we can partition it into "11|00".
+It can be proven that 2 is the minimum number of changes needed to make the string beautiful.
 ```
 
-## 题意
-> ...
+**Example 2:**
 
-## 题解
-
-### 思路1
-> ...
-Minimum Number of Changes to Make Binary String Beautiful
-```go
 ```
+Input: s = "10"
+Output: 1
+Explanation: We change s[1] to 1 to get string "11".
+It can be seen that the string "11" is beautiful because we can partition it into "11".
+It can be proven that 1 is the minimum number of changes needed to make the string beautiful.
+```
+
+**Example 3:**
 
+```
+Input: s = "0000"
+Output: 0
+Explanation: We don't need to make any changes as the string "0000" is beautiful already.
+```
 
 ## 结语
 

leetcode/2901-3000/2914.Minimum-Number-of-Changes-to-Make-Binary-String-Beautiful/Solution.go

@@ -1,5 +1,25 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func Solution(s string) int {
+	ans := 0
+	cur := s[0]
+	c := 1
+	for i := 1; i < len(s); i++ {
+		if s[i] == cur {
+			c = 1 - c
+			continue
+		}
+		if c == 0 {
+			c = 1
+			cur = s[i]
+			continue
+		}
+		ans++
+		i++
+		if i != len(s) {
+			cur = s[i]
+			c = 1
+		}
+	}
+	return ans
 }

leetcode/2901-3000/2914.Minimum-Number-of-Changes-to-Make-Binary-String-Beautiful/Solution_test.go

@@ -10,12 +10,12 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		inputs string
+		expect int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", "1001", 2},
+		{"TestCase2", "10", 1},
+		{"TestCase3", "0000", 0},
 	}
 
 	//	开始测试
@@ -30,10 +30,10 @@ func TestSolution(t *testing.T) {
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }