Add solution and test-cases for problem 2115

leetcode/2101-2200/2115.Find-All-Possible-Recipes-from-Given-Supplies/README.md

@@ -1,28 +1,43 @@
 # [2115.Find All Possible Recipes from Given Supplies][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+You have information about `n` different recipes. You are given a string array `recipes` and a 2D string array `ingredients`. The `ith` recipe has the name `recipes[i]`, and you can **create** it if you have **all** the needed ingredients from `ingredients[i]`. Ingredients to a recipe may need to be created from other recipes, i.e., `ingredients[i]` may contain a string that is in `recipes`.
+
+You are also given a string array `supplies` containing all the ingredients that you initially have, and you have an infinite supply of all of them.
+
+Return a list of all the recipes that you can create. You may return the answer in **any order**.
+
+Note that two recipes may contain each other in their ingredients.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: recipes = ["bread"], ingredients = [["yeast","flour"]], supplies = ["yeast","flour","corn"]
+Output: ["bread"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
 ```
 
-## 题意
-> ...
-
-## 题解
+**Example 2:**
 
-### 思路1
-> ...
-Find All Possible Recipes from Given Supplies
-```go
 ```
+Input: recipes = ["bread","sandwich"], ingredients = [["yeast","flour"],["bread","meat"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+```
+
+**Example 3:**
 
+```
+Input: recipes = ["bread","sandwich","burger"], ingredients = [["yeast","flour"],["bread","meat"],["sandwich","meat","bread"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich","burger"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+We can create "burger" since we have the ingredient "meat" and can create the ingredients "bread" and "sandwich".
+```
 
 ## 结语
 

leetcode/2101-2200/2115.Find-All-Possible-Recipes-from-Given-Supplies/Solution.go

@@ -1,5 +1,63 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func Solution(recipes []string, ingredients [][]string, supplies []string) []string {
+	sm := make(map[string]struct{})
+	rm := make(map[string]struct{})
+	for _, s := range supplies {
+		sm[s] = struct{}{}
+	}
+	for _, r := range recipes {
+		rm[r] = struct{}{}
+	}
+
+	in := make(map[string]int)
+	unlock := make(map[string][]string)
+	for idx, r := range recipes {
+		in[r] = 0
+		for _, i := range ingredients[idx] {
+			if _, ok := sm[i]; ok {
+				continue
+			}
+			if i == r {
+				in[r] = -1
+				break
+			}
+			if _, ok := rm[i]; ok {
+				in[r]++
+				if _, ok := unlock[i]; !ok {
+					unlock[i] = []string{}
+				}
+				unlock[i] = append(unlock[i], r)
+				continue
+			}
+			in[r] = -1 // 无法组成,用了一些不存在的东西
+			break
+		}
+	}
+	res := []string{}
+	queue := []string{}
+	for r, c := range in {
+		if c == 0 {
+			queue = append(queue, r)
+			res = append(res, r)
+		}
+	}
+	for len(queue) > 0 {
+		nq := make([]string, 0)
+		for _, cur := range queue {
+			for _, r := range unlock[cur] {
+				in[r]--
+				if in[r] == 0 {
+					nq = append(nq, r)
+					res = append(res, r)
+				}
+			}
+		}
+		if len(nq) == 0 {
+			break
+		}
+		queue = nq
+	}
+
+	return res
 }

leetcode/2101-2200/2115.Find-All-Possible-Recipes-from-Given-Supplies/Solution_test.go

@@ -2,38 +2,42 @@ package Solution
 
 import (
 	"reflect"
+	"sort"
 	"strconv"
 	"testing"
 )
 
 func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
-		name   string
-		inputs bool
-		expect bool
+		name        string
+		recipes     []string
+		ingredients [][]string
+		supplies    []string
+		expect      []string
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []string{"bread"}, [][]string{{"yeast", "flour"}}, []string{"yeast", "flour", "conr"}, []string{"bread"}},
+		{"TestCase2", []string{"bread", "sandwich"}, [][]string{{"yeast", "flour"}, {"bread", "meat"}}, []string{"yeast", "flour", "meat"}, []string{"bread", "sandwich"}},
+		{"TestCase3", []string{"bread", "sandwich", "burger"}, [][]string{{"yeast", "flour"}, {"bread", "meat"}, {"sandwich", "meat", "bread"}}, []string{"yeast", "flour", "meat"}, []string{"bread", "burger", "sandwich"}},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.recipes, c.ingredients, c.supplies)
+			sort.Strings(got)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
+					c.expect, got, c.recipes, c.ingredients, c.supplies)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }