How to get size of the array in Adept?

[ghost]

I mean primitive fixed array.

This code doesn't work:

N uint = 10
arr [N] uint

But this code works:

arr [10] uint

I don't want to have to remember the size of arr, especially when using for loops. This means I will need a way to get the size of arr and assign it to the variable N.

[IsaacShelton]

Adept doesn't let use you runtime variables for array sizes, you can either do:

func lengthof(array *[$#N] $T) usize = $#N

func main {
    arr [10] uint
    for(i usize = 0; i < lengthof(&arr); i++){
        // ...
    }
}

or

func main {
    arr [10] uint
    for(i usize = 0; i < sizeof(arr) / sizeof(arr[0]); i++){
        // ...
    }
}

or

#define N 10

func main {
    arr [#get N] uint
    for(i usize = 0; i < #get N; i++) {
        // ...
    }
}

[ghost]

I will go with the C-like sizeof trick. Thank you.