Fix foreign key violation error messages to include key value and table name

[Copilot]

Fix foreign key violation error message to show table and key information (Issue #1009)

• Created test file test1009.js to demonstrate the issue
• Identified the two locations where foreign key errors are thrown
• Update inline foreign key error message (line 177-179)
• Update constraint foreign key error message (line 267-270)
• Run tests to verify the fix - all passing
• Format code with prettier
• Run code review - not applicable (changes already committed)
• Run security checks - no vulnerabilities found
• Refactor test file to use multi-statement SQL strings per code review

Summary

Fixed the foreign key violation error messages in AlaSQL to include meaningful information about which key and table failed validation. Previously, the error message was simply "Foreign key violation" without any details about what failed.

Changes Made

1. Inline Foreign Keys (line 177-179 in src/60createtable.js):

   • Changed error message to include the actual key value and table name
   • Example: Foreign key "99" not found in table "tableC"

2. Constraint Foreign Keys (line 267-273 in src/60createtable.js):

   • Changed error message to include the actual key value(s) and table name
   • Handles composite keys with multiple values
   • Example: Foreign key "99, 99" not found in table "tableE"

Test Coverage

Added comprehensive test file test/test1009.js with three test cases:

• Single column foreign key validation
• Inline foreign key validation
• Composite foreign key validation

All tests verify that:

• Error messages include the foreign key value(s)
• Error messages include the referenced table name
• Error messages do not contain "undefined"

Updated per code review to use multi-statement SQL strings separated by semicolons instead of multiple alasql() calls.

Security Summary

No security vulnerabilities introduced by these changes. CodeQL analysis found 0 alerts.

Original prompt

---

This section details on the original issue you should resolve

<issue_title>Error in exception message for foreign key violation error</issue_title>
<issue_description>When trying to insert a row into table B that references table A, if the referenced primary key in table A doesn't exist then alasql throw an exception. But the name of the table with the missing primary key is shown as undefined in the message:

C:\<path>\node_modules\alasql\dist\alasql.fs.js:12796
Error: Foreign key "20" is not found in table undefined

</issue_description>

<agent_instructions>Please help me confirm if this is still an issue. Start by making a testfile named test1009.js and demonstrate. If its a problem then please seek to solve it. </agent_instructions>

Comments on the Issue (you are @copilot in this section)

@mathiasrw Hi @zachsa - Really glad you are reaching out so we can make a better library.

Is it because it would make more sense if it stated Error: Foreign key "20" is not found in table not defined?</comment_new>
<comment_new>@mathiasrw
@Rudy167 any change you could provide a Pull Request with the code?</comment_new>
<comment_new>@mathiasrw
Seams perfect to me...</comment_new>

• Fixes Error in exception message for foreign key violation error #1009

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[mathiasrw]

@copilot

[Copilot]

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