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Java file updated #1

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11 changes: 11 additions & 0 deletions Java/avg/array.java
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Original file line number Diff line number Diff line change
Expand Up @@ -12,4 +12,15 @@ public static void main(String[] args) {
System.out.println(arr[i]);
}
}

public static void Even(String[] args) {
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Rename the Even method to follow Java naming conventions, using lowerCamelCase, such as 'printEvenNumbers'.
Code Suggestion:

-    public static void Even(String[] args) {
+    public static void printEvenNumbers(String[] args) {

Scanner sc = new Scanner(System.in);
Comment on lines +16 to +17
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Reuse the Scanner instance from the main method instead of creating a new instance in the Even method to reduce redundancy and improve resource management.
Code Suggestion:

+    // Consider passing the Scanner instance from the main method to avoid redundancy
-        Scanner sc = new Scanner(System.in);

int[] arr = new int[]{1, 2, 3, 4, 5};
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Avoid hardcoding the array within the method. Consider passing the array as a parameter to increase the method's flexibility and reusability.
Code Suggestion:

-        int[] arr = new int[]{1, 2, 3, 4, 5};
+        // Consider passing the array as a parameter

System.out.println("Even numbers:");
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Extract the message string to a constant or use it directly in the print statement to avoid unnecessary string creation each time the method is called.
Code Suggestion:

+    private static final String EVEN_NUMBERS_MESSAGE = "Even numbers:";
-        System.out.println("Even numbers:");
+        System.out.println(EVEN_NUMBERS_MESSAGE);


for (int i = 0; i < arr.length; i = i * 2)
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Modify the loop increment from i = i * 2 to i += 2 to correctly iterate over even indices. The current implementation may lead to an infinite loop or ArrayIndexOutOfBoundsException by skipping beyond the array's bounds.
Code Suggestion:

-        for (int i = 0; i < arr.length; i = i * 2)
+        for (int i = 1; i < arr.length; i += 2)

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@Amruta101998 Amruta101998 Mar 28, 2024

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Optimization Issue: The loop increment i = i * 2 in the 'Even' method results in an infinite loop when i is 0, leading to a severe performance issue. This can cause the application to hang or crash, especially when handling large arrays.
Fix: Change the loop increment to i += 2, which ensures the loop iterates through even-indexed elements without causing an infinite loop.
Code Suggestion:

for (int i = 0; i < arr.length; i += 2)
        {
            System.out.println(arr[i]);
        }

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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Modify the loop condition to ensure it iterates correctly over even indices without causing an ArrayIndexOutOfBoundsException. Consider using 'i += 2' instead of 'i = i * 2' to iterate through even indices.
Code Suggestion:

-        for (int i = 0; i < arr.length; i = i * 2)
+        for (int i = 1; i < arr.length; i += 2)

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@Amruta101998 Amruta101998 Mar 28, 2024

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Scalability Issue: The loop increment 'i = i * 2' can lead to an infinite loop for arrays of size greater than 1, severely impacting scalability by causing unnecessary CPU usage and potentially crashing the system under high load.
Fix: Change the loop increment to a more predictable and terminating condition, such as 'i += 2' for iterating over even indices, ensuring the loop terminates correctly.
Code Suggestion:

for (int i = 0; i < arr.length; i += 2) {
    System.out.println(arr[i]);
}

{
System.out.println(arr[i]);
}
Comment on lines +21 to +24
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Consider adding error handling or a check to ensure the array is not null or empty before attempting to print even numbers to avoid potential NullPointerExceptions or unexpected behavior.
Code Suggestion:

+        if (arr == null || arr.length == 0) return;
+        for (int i = 1; i < arr.length; i += 2)

}
Comment on lines +16 to +25
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Consider renaming the method from Even to printEvenIndexedElements to follow Java naming conventions and improve readability. Refactor the method to eliminate code duplication, specifically the Scanner initialization and array declaration which are already present in the main method. Optimize the loop condition to ensure it correctly processes even indices without risking an ArrayIndexOutOfBoundsException.
Code Suggestion:

-    public static void Even(String[] args) {
+    public static void printEvenIndexedElements(int[] arr) {
+        System.out.println("Even numbers:");
+        for (int i = 1; i < arr.length; i += 2)

Comment on lines +16 to +25
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@Amruta101998 Amruta101998 Mar 28, 2024

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Code Structure Issue: The method Even is incorrectly named according to Java naming conventions. Method names should start with a lowercase letter and follow camelCase notation.
Fix: Rename the method from 'Even' to 'even' to adhere to Java naming conventions.
Code Suggestion:

public static void even(String[] args)

Comment on lines +16 to +25
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@Amruta101998 Amruta101998 Mar 28, 2024

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Code Structure Issue: The method Even is incorrectly named according to Java naming conventions. Method names should start with a lowercase letter and follow camelCase notation.
Fix: Rename the method from "Even" to "printEvenNumbers" to clearly describe its functionality and adhere to Java naming conventions.
Code Suggestion:

public static void printEvenNumbers(String[] args) {
    Scanner sc = new Scanner(System.in);
    int[] arr = new int[]{1, 2, 3, 4, 5};
    System.out.println("Even numbers:");

    for (int i = 0; i < arr.length; i += 2) {
        System.out.println(arr[i]);
    }
}

}
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@Amruta101998 Amruta101998 Mar 28, 2024

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Suggestion: Ensure proper cleanup of resources, such as closing the Scanner instance, to prevent resource leaks. Consider implementing a try-with-resources statement if applicable.
Code Suggestion:

+        sc.close();