[강병호] Day20

leetcode2/1easy/강병호/Q3114.py

@@ -0,0 +1,34 @@
+class Solution:
+    def findLatestTime(self, s: str) -> str:
+        # i - 0 : i - 1과 연관 / 3이상이면 무조건 0
+        # i - 1 : i - 0과 연관 / 1이면 0~2
+        time = list(s)
+
+        t0, t1 = time[0], time[1]
+
+
+        if t0 == '?':
+            if t1 == '?':
+                t0 = '1'
+            else:
+                t0 = '1' if int(t1) <= 1 else '0'
+
+        time[0] = t0
+
+        if t1 == '?':
+            t1 = '1' if time[0] == '1' else '9'
+        time[1] = t1
+
+        t3, t4 = time[3], time[4]
+        if t3 == '?':
+            t3 = '5'
+        time[3] = t3
+
+        if t4 == '?':
+            t4 = '9'
+        time[4] = t4
+
+        return ''.join(time)
+
+
+