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The Radon transform convolves the image with a circle whose integral is the length of the perimeter. With the normalize option its integral is 1 (it is the convolution kernel that is normalized, not the image). Either way the peak intensities in the Radon space scale with image intensities.

However, compared to the Hough transform, the Radon space is very smooth, and there are many fewer spurious local maxima. That is why the default threshold value is rather low. It really only comes into play when the circles are not really circular.

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@crisluengo
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@crisluengo
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@anntzer
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@crisluengo
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@anntzer
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Answer selected by anntzer
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