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yerim01
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Mar 7, 2026
| fun containsDuplicate(nums: IntArray): Boolean { | ||
| val set = HashSet<Int>() | ||
| for (num in nums) { | ||
| if (set.contains(num)) { |
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코틀린에서도 contains를 쓰는군요 잘 보았습니다!
yerim01
reviewed
Mar 7, 2026
| val complement = target - nums[index] | ||
| val complementIndices = map[complement] | ||
| if (complementIndices != null) { | ||
| for (complementIndex in complementIndices) { |
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complementIndices를 순회 하는 부분에서 중첩 for loop 이 생기면서 time complexity가 O(n^2)이 될 수도 있을 것 같은데 제가 이해한게 맞을까요?
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이 complementIndices는 최대 사이즈가 2입니다. :)
그래서 n^2와 같은 성능으로 동작하진 않는다고 볼수 있습니다.
acious
commented
Mar 7, 2026
| @@ -0,0 +1,19 @@ | |||
| class Solution { | |||
| // 시간복잡도 : O(n) : map 세팅, O(nlogn) : map value 정렬 = O(nlogn) | |||
| fun topKFrequent(nums: IntArray, k: Int): IntArray { | |||
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이건 성능이 꽤 나쁘게 책정되었는데 더 나은 솔루션을 시간이 없어서 적용하지 못했네요.
yerim01
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Mar 7, 2026
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이번주도 수고하셨습니다! 다음주도 화이팅해요.
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