Use longs for swindlers, allowing even bigger swindlers #791
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I hate it but I love it |
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I did some math and this should allow swindling up to 18 elements. Certain 19-long swindles should also be allowed. (The bottleneck is that the number is a double, so the highest integer you can represent cleanly is 2^53. See https://stackoverflow.com/questions/1848700/biggest-integer-that-can-be-stored-in-a-double) |
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issue observed by cjcool1 in discord. I have no clue what he was doing that needed a swindler of 12+ items but hey it works now