Custom logout navigates without being called

[SEGVeenstra]

Has your issue been reported?

• I have searched the existing issues and confirm it has not been reported.
• I give permission for members of the FlutterFlow team to access and test my project for the sole purpose of investigating this issue.

Current Behavior

The app should not navigate when the user cancels the logout dialog.

Expected Behavior

Even if the user cancels the dialog, the app still navigates to the login screen.

Steps to Reproduce

1. Create a login page that uses custom login for authentication.
2. Create a homepage for the when the user is logged in.
3. Add a logout button
4. Add the actions as follow:

1. Test the app

Now whatever option you pick, cancel or logout, both will result in the app navigating to the login page.

Reproducible from Blank

• The steps to reproduce above start from a blank project.

Bug Report Code (Required)

IT5Thc/1z4hOsdtK+KryccBvgiYvNl87aucziu1EFBQaJuvoB7QHPPekbXFJOum4TAk7CmeWmjsypq3Zud7DGMEnHxGrbLlq3bl2FA/xQlujRLrUPKrtREdREppWfHLG3KaO2wx9G7FaLXg+1F6bOOjJQgDaGJOwNjMnBPyjMt7+kVKUKxDsGiFrxidecCfn

Context

I need the user to stay on the homepage if they cancel the logout request so they can continue using the app.
Other aspects are working, like retaining the user loggedin state.

Visual documentation

Additional Info

No response

Environment

- FlutterFlow version: 4.1
- Platform: Mac
- Browser name and version: Chrome 120.0.6099.216 (Officiële build) (x86_64)
- Operating system and version affected:

[hariprasadms]

Hi @SEGVeenstra - Thanks for submitting the issue - You should add terminate step to stop the action execution. See below.

[SEGVeenstra]

Hi @SEGVeenstra - Thanks for submitting the issue - You should add terminate step to stop the action execution. See below.

Thank you for your reply.
Can you tell me why that is needed?

Why does it perform the navigation even though that part of the condition is not met?

[Franco98404]

Can you tell me why that is needed?

Why does it perform the navigation even though that part of the condition is not met?

Hello @hariprasadms, I have the same doubts. I appreciate it if you give us an explanation :)