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Original file line number Diff line number Diff line change
Expand Up @@ -13,7 +13,7 @@

It seems that in astronomy, there is a relationship between the image resolution $\theta$ and the wavelength $\lambda$ giving by

$$ \theta = 1.22 \frac{\lambda} {D} $$
$\theta = 1.22 \frac{\lambda} {D}$

- Where $D$ is the diameter of the telescope.
- to get better resolution (small $\theta$), we need:
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6 changes: 4 additions & 2 deletions resources/links/Angular resolution.md
Original file line number Diff line number Diff line change
Expand Up @@ -11,9 +11,11 @@

**_SO THE GOAL BECOMES HOW TO MAKE IMAGES WITH SMALL ANGULAR RESOLUTIONS._**

It seems that in astronomy, there is a relationship between the image resolution $\theta$ and the wavelength $\lambda$ giving by
It seems that in astronomy, there is a relationship between the image resolution $\theta$ and the wavelength $\lambda$ giving by:


$$\theta = 1.22 \frac{\lambda} {D}$$

$$ \theta = 1.22 \frac{\lambda} {D} $$

- Where $D$ is the diameter of the telescope.
- to get better resolution (small $\theta$), we need:
Expand Down