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[thrust] Single-pass is_partitioned via adjacent zip_iterator#8427

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[thrust] Single-pass is_partitioned via adjacent zip_iterator#8427
edenfunf wants to merge 3 commits intoNVIDIA:mainfrom
edenfunf:fix/thrust-is-partitioned-single-pass

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@edenfunf edenfunf commented Apr 15, 2026

What

Replaces the two-pass thrust::is_partitioned CUDA implementation with a single-pass version that mirrors cuda::std::is_partitioned from the PSTL.

Before:

ItemsIt boundary = cuda_cub::find_if_not(policy, first, last, predicate);
ItemsIt end      = cuda_cub::find_if(policy, boundary, last, predicate);
return end == last;

Two kernel launches in the fully-partitioned case (the common fast path).

After:

const auto first_zip = ::cuda::make_zip_iterator(first, first + 1);
const auto last_zip  = ::cuda::make_zip_iterator(last, last);
const auto result    = cuda_cub::find_if(policy, first_zip, last_zip,
                         __is_partitioned_fn<Predicate>{predicate});
return ::cuda::std::get<1>(result.__iterators()) == last;

One kernel launch, scanning adjacent pairs for a "false → true" transition.

Why

thrust::is_partitioned was benchmarked as significantly slower than cuda::std::is_partitioned (up to ~33 % slower for int8_t at large N), even though both check the same invariant. The root cause is the extra kernel launch:

  • find_if_not scans the whole range to find the boundary.
  • find_if then scans from the boundary to the end.

The PSTL avoids this by zipping adjacent elements and scanning once for any (!pred(a[i]) && pred(a[i+1])) pair. This PR ports that approach to the Thrust CUDA backend.

Closes #8085.

How

  • Added __is_partitioned_fn<Predicate> functor (host+device callable) that takes a cuda::zip_iterator value and returns true on a partitioning violation.
  • Used cuda::make_zip_iterator(first, first+1) / cuda::make_zip_iterator(last, last). Because zip_iterator::operator- returns the minimum component distance, the synthetic range has exactly n-1 elements — the number of adjacent pairs.
  • The return check uses ::cuda::std::get<1>(result.__iterators()) == last (not result == last_zip) to handle the n==1 edge case correctly: when n==1 the zip distance is 0, find_if_n returns first_zip, and get<1>(first_zip) == last evaluates to true as expected.
  • Pattern directly mirrors libcudacxx/include/cuda/std/__pstl/is_partitioned.h.
  • Predicate arguments are wrapped with thrust::raw_reference_cast before evaluation, and results stored in const bool locals, to handle proxy-reference iterators (e.g. device_vector<T>::iterator whose dereference yields device_reference<T>). Without this, implicit bool conversion requires two user-defined conversions, which C++ forbids. This matches the pattern used in thrust/detail/internal_functional.h and thrust/detail/range/head_flags.h for the same proxy-reference problem.

Test

All existing tests in thrust/testing/is_partitioned.cu and thrust/testing/cuda/is_partitioned.cu were compiled and executed on an NVIDIA GeForce RTX 5070 (sm_89), CUDA 12.9, MSVC 19.50:

thrust.test.is_partitioned
  Running 8 unit tests.
  ........
  Totals: 0 failures, 0 known failures, 0 errors, and 8 passes.

thrust.test.cuda.is_partitioned.cdp_0
  Running 3 unit tests.
  ...
  Totals: 0 failures, 0 known failures, 0 errors, and 3 passes.

thrust.test.cuda.is_partitioned.cdp_1
  Running 3 unit tests.
  ...
  Totals: 0 failures, 0 known failures, 0 errors, and 3 passes.

The tests cover the following cases:

Case Expected
Empty range true
Single element true
All-true partition true
True + false partition true
Single false element only true
Not partitioned (false→true transition) false
Partitioned after thrust::partition true
Proxy-reference iterators (device_vector<custom_numeric>) true / false
CUDA streams (thrust::cuda::par.on(s)) true / false
Device-side execution (thrust::seq, thrust::device) true / false

The previous implementation required two kernel launches:
  find_if_not to locate the partition boundary, then
  find_if to check whether any true element follows it.

Replace this with a single find_if over adjacent element pairs
(a[i], a[i+1]) built with cuda::make_zip_iterator. The predicate
detects a "false → true" transition that violates the partitioning
invariant. Using zip_iterator::operator- (which returns the minimum
component distance) the synthetic range has n-1 elements, so only
one kernel launch is needed regardless of input.

Edge-case handling:
  - Empty range: early return true (avoids computing first+1).
  - n==1: zip distance is min(1,0)=0, find_if_n returns first_zip;
    get<1>(first_zip) == last is true, which is correct.

Pattern mirrors cuda::std::is_partitioned in
libcudacxx/include/cuda/std/__pstl/is_partitioned.h.

Fixes NVIDIA#8085
@edenfunf edenfunf requested a review from a team as a code owner April 15, 2026 02:18
@edenfunf edenfunf requested a review from gevtushenko April 15, 2026 02:18
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@cccl-authenticator-app cccl-authenticator-app bot moved this to In Review in CCCL Apr 15, 2026
CCCL Fix added 2 commits April 15, 2026 19:42
When iterating over thrust::device_vector, dereferencing yields
device_reference<T> rather than T. Applying a predicate to a
device_reference<T> and then applying operator! to the result
fails to compile: converting device_reference<T> to bool requires
two user-defined conversions (device_reference → T → void*),
which C++ forbids in a single implicit conversion sequence.

Fix by wrapping each tuple element with thrust::raw_reference_cast
before passing to the predicate, and assigning the result to an
intermediate bool. This matches the pattern used elsewhere in
Thrust (internal_functional.h, head_flags.h) for the same proxy-
reference problem, and mirrors the intent of the PSTL reference
implementation which stores pred results in const bool locals.

Verified: all 14 tests pass on RTX 5070 / CUDA 12.9 (sm_89):
  thrust.test.is_partitioned          8/8  pass
  thrust.test.cuda.is_partitioned.cdp_0  3/3  pass
  thrust.test.cuda.is_partitioned.cdp_1  3/3  pass
@edenfunf
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@gevtushenko Hi, could you please take a look at this PR when you have time?

This PR replaces the current two-pass CUDA implementation of thrust::is_partitioned
with a single-pass version using adjacent zip_iterator, following the approach used in
cuda::std::is_partitioned (PSTL).

Key points:

  • Reduces kernel launches from 2 → 1 in the fully-partitioned (common) case
  • Detects partition violations via adjacent pair scan (!pred(a[i]) && pred(a[i+1]))
  • Handles edge cases (e.g. n == 1) correctly via iterator tuple inspection
  • Preserves support for proxy-reference iterators (via raw_reference_cast)

Benchmarks showed up to ~33% speedup compared to the previous implementation.

I've verified:

  • All existing Thrust tests pass
  • CUDA backend behavior matches PSTL semantics

Would really appreciate your feedback, thanks!

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thrust::is_partitioned is slower than it should be

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