|
for i in range(self.n_ele): |
|
estimation[:, t] += estimation_table[:, i]*beta[i] # C*(x) Eq 18 |
is IMHO mathematically equivalent with:
estimation[:, t] = np.dot(estimation_table, beta)
which should be faster.
However, the obtained results may differ due to numerical issues.
kCSD-python/kcsd/KCSD.py
Lines 219 to 220 in 2ce755a
is IMHO mathematically equivalent with:
which should be faster.
However, the obtained results may differ due to numerical issues.