Add iterations from 1 to 3

js/index.js

@@ -1,7 +1,45 @@
 // Iteration 1: Names and Input
 
+console.log("I'm ready!");
+let hacker1 = "Manuel";
+console.log(`The driver's name is ${hacker1}`);
+let hacker2 = "Sofía";
+console.log(`The navigator\'s name is ${hacker2}`);
 
 // Iteration 2: Conditionals
 
+let driver = hacker1;
+let navigator = hacker2;
+function findTheLongest(str1, str2) {
+  if (str1.length > str2.length) {
+    return `The driver has the longest name, it has ${driver.length} characters.`;
+  } else if (str1.length < str2.length) {
+    return `It seems that the navigator has the longest name, it has ${navigator.length} characters.`;
+  } else {
+    return `Wow, you both have equally long names, ${driver.length} characters!`;
+  }
+}
+console.log(findTheLongest(driver, navigator));
 
-// Iteration 3: Loops
+// Iteration 3: Loops
+
+function printWhitEmphasis(str) {
+  str = str.toUpperCase().split("");
+  return str.join(" ");
+}
+console.log(printWhitEmphasis(driver));
+function printReverse(str) {
+  str = str.split("").reverse();
+  return str.join("");
+}
+console.log(printReverse(navigator));
+function lexicographicOrder(str1, str2) {
+  if (str1.localeCompare(str2) < 0) {
+    return `The driver\'s name goes first.`;
+  } else if (str1.localeCompare(str2) > 0) {
+    return `Yo, the navigator goes first definitely.`;
+  } else {
+    return `What?! You both have the same name?`;
+  }
+}
+console.log(lexicographicOrder(driver, navigator));