Binary Base 2 Math + Logic Gates

[zachpeltz]

Popcorn Hack 1:

• 101010 is binary because all numbers are 1s and 0s
• 12301 is not because it has a 2 and a 3
• 11001 is binary all 1s and 0s

Popcorn Hack 2:

• 101+110 = 1011
• 1101-1011 = 010
• 111+1001 = 1110

Popcorn Hack 3:

• The result of True or False and False is True since and has priority over or

Popcorn Hack 4:

• The result of Not True and False is False since not is evaluated first

Popcorn Hack 5:

• The result of True or False and not false is true because and/not are evaluated first

HW Hack 1:

Convert Decimal to Binary

def decimal_to_binary(decimal_number):
if decimal_number >= 0:
return bin(decimal_number)[2:] # Remove the '0b' prefix
else:
return '-' + bin(abs(decimal_number))[2:] # Handle negatives

Convert Binary to Decimal

def binary_to_decimal(binary_string):
if binary_string.startswith('-'):
return -int(binary_string[1:], 2)
else:
return int(binary_string, 2)

Test the functions

print("Decimal to Binary:")
print("10 →", decimal_to_binary(10))
print("-15 →", decimal_to_binary(-15))

print("\nBinary to Decimal:")
print("1010 →", binary_to_decimal("1010"))
print("-1111 →", binary_to_decimal("-1111"))

HW Hack 2:
import time

difficulty = input("Enter difficulty (easy, medium, hard): ").lower().strip()

Use and instead of or for correct logic

while difficulty not in ["easy", "medium", "hard"]:
print("Please enter a valid difficulty level.")
time.sleep(0.5)
difficulty = input("Enter difficulty (easy, medium, hard): ").lower().strip()

print("Difficulty set to:", difficulty)