Runestone Issue: 10.3 Parsons (dandf_pp_count_each_letter_rev) Incorrect Code

[taborasykes]

Please check the current issues
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Describe the bug
Line 8 should be "word_count[word] = 0" because a word not already in the word_count dictionary will initially be counted twice due to the lack of an else statement preceding line 9.

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sykesta@vcu.edu

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Thank you for the interactive textbook!

[taborasykes]

This was from the Python for Everybody interactive textbook.

[barbarer]

What chapter and page is it on?

[barbarer]

Nevermind. I found it. Good catch. It has been fixed.