fix: Fix MemorySegment::Compare to use big-endian byte-order comparison semantics#298
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Purpose
No Linked issue.
Problem
MemorySegment::Comparereads 8 bytes at a time usingGetValue<int64_t>()which returns the value in native endianness. On little-endian platforms (x86/ARM), this breaks lexicographic (byte-order) comparison semantics — the most significant byte in memory becomes the least significant byte in the integer, causing incorrect comparison results.For example, comparing
[0x00, 0x01, 0, 0, 0, 0, 0, 0]vs[0x01, 0x00, 0, 0, 0, 0, 0, 0]:0x00 < 0x01, result should be negative0x0100 > 0x0001, result was positive ❌This is consistent with the existing TODO in the code and aligned with the Java implementation which uses
getLongBigEndian().Fix
GetLongBigEndian()method toMemorySegmentthat reads 8 bytes and converts to big-endian order using the existingEndianSwapValue()utility frommath.hCompare()to callGetLongBigEndian()instead of rawGetValue<int64_t>()Tests
MemorySegmentTest.TestCompare
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