derivation: Boyle's law, simple; rewrite of chem.libretexts.org

[bhpayne]

• https://www.pw.live/exams/school/boyles-law-formula/
• https://physics.stackexchange.com/questions/99347/deriving-combined-gas-law-from-boyles-and-charles-laws
• https://physics.stackexchange.com/questions/693255/can-we-derive-boyles-law-out-of-nothing
• https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Thermodynamics_and_Chemical_Equilibrium_(Ellgen)/02%3A_Gas_Laws/2.10%3A_Deriving_Boyle's_Law_from_Newtonian_Mechanics
• https://byjus.com/chemistry/boyles-law/

[bhpayne]

prompt to Gemini 2.0 Flash Thinking Experimental 01-21 https://aistudio.google.com/prompts/

Convert the following HTML content to a single Latex document.

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<P>We can derive <a title="2.1: Boyle's Law" href="https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Thermodynamics_and_Chemical_Equilibrium_(Ellgen)/02%3A_Gas_Laws/2.01%3A_Boyle's_Law" rel="internal">Boyle&rsquo;s law</a> from Newtonian mechanics. This derivation assumes that gas molecules behave like point masses that do not interact with one another. The pressure of the gas results from collisions of the gas molecules with the walls of the container. The contribution of one collision to the force on the wall is equal to the change in the molecule&rsquo;s momentum divided by the time between collisions. The magnitude of this force depends on the molecule&rsquo;s speed and the angle at which it strikes the wall. Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall. To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle&rsquo;s law in this way.</p>

<P>We can do a simplified derivation by making a number of assumptions. We assume that all of the molecules in a sample of gas have the same speed. Let us call it \(u\). As sketched in Figure 3, we assume that the container is a cubic box whose edge length is \(d\). If we consider all of the collisions between molecules and walls, it is clear that each wall will experience \({1}/{6}\) of the collisions; or, each pair of opposing walls will experience \({\mathrm{1}}/{\mathrm{3}}\) of the collisions. Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box. Since they are point masses, they never collide with one another. If we suppose that \({\mathrm{1}}/{\mathrm{3}}\) of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds. In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4.</p>

<figure><figcaption>Figure 3.  Simplified model for velocities of gas molecules in a cubic box.</figcaption></figure>

<P>Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule&rsquo;s speed remains constant, but its direction changes by 180\({}^{o}\); that is, the molecule&rsquo;s velocity changes from \(\mathop{u}\limits^{\rightharpoonup}\) to \(-\mathop{u}\limits^{\rightharpoonup}\). Letting \(\Delta t\) be the time required for a round trip, the distance traversed in a round trip is</p>

<P>\[\begin{aligned} 2d &amp; =\left|\mathop{u}\limits^{\rightharpoonup}\right|\Delta t \\ ~ &amp; =u\Delta t \end{aligned} \nonumber \]</p>

<P>The magnitude of the momentum change for a molecule in one collision is</p>

<p>\[\begin{align*} \left|\Delta (m\mathop{u}\limits^{\rightharpoonup})\right| &amp;=\left|m{\mathop{u}\limits^{\rightharpoonup}}_{final}-m{\mathop{u}\limits^{\rightharpoonup}}_{initial}\right| \\[4pt] &amp;=\left|m{\mathop{u}\limits^{\rightharpoonup}}_{final}-\left({-m\mathop{u}\limits^{\rightharpoonup}}_{final}\right)\right| \\[4pt] &amp;=2mu \end{align*}  \nonumber \]</p>

<P>The magnitude of the force on the wall from one collision is</p>

<P>\[F=\frac{\left|\Delta \left(m\mathop{u}\limits^{\rightharpoonup}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d} \nonumber \]</p>

<P>and the pressure contribution from one collision on the wall, of area \(d^2\), is</p>

<P>\[P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V} \nonumber \]</p>

<P>so that we have</p>

<P>\[PV=mu^2 \nonumber \]</p>

<P>from the collision of one molecule with one wall.</p>

<P>If the number of molecules in the box is \(N\), \(N/3\) of them make collisions with this wall, so that the total pressure on one wall attributable to all \(N\) molecules in the box is</p>

<P>\[P=\frac{mu^2}{V}\frac{N}{3} \nonumber \]</p>

<P>or</p>

<P>\[PV=\frac{Nmu^2}{3} \nonumber \]</p>

<P>Since the ideal gas equation can be written as \(PV=NkT\) we see that \({Nmu^2}/{3}=NkT\) so that \(mu^2=3kT\) and</p>

<P>\[u=\sqrt{\frac{3kT}{m}} \nonumber \]</p>

<P>Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, \(v\), can have any value between zero and&mdash;for present purposes&mdash;infinity. When we average the values of \(v^2\) for many molecules, we find the average value of the squared speeds, \(\overline{v^2}\). In Chapter 4, we find that \(u^2=\overline{v^2}\). That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, \(v_{rms}=u=\sqrt{\overline{v^2}}\).) This result also gives us the (average) kinetic energy of a single gas molecule:</p>

<P>\[KE=\frac{mu^2}{2}=\frac{3kT}{2} \nonumber \]</p>

<P>From this derivation, we have a simple mechanical model that explains Boyle&rsquo;s law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature</em>.</strong></p>

<P>Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules&rsquo; kinetic energy.) The energy of one mole of monatomic ideal gas molecules is</p>

<P>\[KE=\left({3}/{2}\right)RT \nonumber \]</p>

<P>When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than \(\left({3}/{2}\right)RT\), because of the energy associated with these additional motions.</p>

<P>We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that</p>

<P>\[{\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0 \nonumber \]</p>

<P>for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature.</p>

<P>While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule&rsquo;s early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy.</p>

<P>Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.) 

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• 2d = |\mathop{u}\limits^{\rightharpoonup}|\Delta t = u\Delta t -> \begin{equation} 2d = |\mathop{u}\limits^{\rightharpoonup}|\Delta t = u\Delta t \label{eq:round-trip-distance} \end{equation} (Round trip distance and time relation)
• |\Delta (m\mathop{u}\limits^{\rightharpoonup})| = |m{\mathop{u}\limits^{\rightharpoonup}}_{final}-m{\mathop{u}\limits^{\rightharpoonup}}_{initial}| = |m{\mathop{u}\limits^{\rightharpoonup}}_{final}-({-m\mathop{u}\limits^{\rightharpoonup}}_{final})| = 2mu -> \begin{equation} \left|\Delta (m\mathop{u}\limits^{\rightharpoonup})\right| =\left|m{\mathop{u}\limits^{\rightharpoonup}}_{final}-m{\mathop{u}\limits^{\rightharpoonup}}_{initial}\right| =\left|m{\mathop{u}\limits^{\rightharpoonup}}_{final}-\left({-m\mathop{u}\limits^{\rightharpoonup}}_{final}\right)\right| =2mu \label{eq:momentum-change} \end{equation} (Momentum change during collision)
• F=\frac{\left|\Delta \left(m\mathop{u}\limits^{\rightharpoonup}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d} -> \begin{equation} F=\frac{\left|\Delta \left(m\mathop{u}\limits^{\rightharpoonup}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d} \label{eq:force-one-collision} \end{equation} (Force from one collision)
• P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V} -> \begin{equation} P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V} \label{eq:pressure-one-collision} \end{equation} (Pressure from one collision)
• PV=mu^2 -> \begin{equation} PV=mu^2 \label{eq:PV-one-molecule} \end{equation} (PV for one molecule)
• P=\frac{mu^2}{V}\frac{N}{3} -> \begin{equation} P=\frac{mu^2}{V}\frac{N}{3} \label{eq:pressure-N-molecules} \end{equation} (Pressure for N molecules)
• PV=\frac{Nmu^2}{3} -> \begin{equation} PV=\frac{Nmu^2}{3} \label{eq:PV-N-molecules} \end{equation} (PV for N molecules)
• u=\sqrt{\frac{3kT}{m}} -> \begin{equation} u=\sqrt{\frac{3kT}{m}} \label{eq:rms-speed} \end{equation} (RMS speed)
• KE=\frac{mu^2}{2}=\frac{3kT}{2} -> \begin{equation} KE=\frac{mu^2}{2}=\frac{3kT}{2} \label{eq:kinetic-energy-molecule} \end{equation} (Kinetic energy of a molecule)
• KE=\left({3}/{2}\right)RT -> \begin{equation} KE=\left(\frac{3}{2}\right)RT \label{eq:kinetic-energy-mole} \end{equation} (Kinetic energy of a mole)
• {\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0 -> \begin{equation} {\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0 \label{eq:energy-independent-VP} \end{equation} (Energy independent of volume and pressure for ideal gas)

Let's put it all together in the LaTeX document. Need to handle math symbols like \mathop{u}\limits^{\rightharpoonup}, \Delta, \left| ... \right|, fractions, square roots, partial derivatives, etc. Use amsmath package for equation environments.

Review and refine labels to be more descriptive if needed. For example, eq:rms-speed is good, but eq:PV-one-molecule could be eq:PV-law-single-molecule. But let's keep them concise for now.

After writing the LaTeX code, compile it to check for errors and verify the output.

response

\documentclass{article}
\usepackage{amsmath}
\usepackage{amsfonts} % For \mathbb{R}

\begin{document}

\noindent We can derive Boyle's law from Newtonian mechanics. This derivation assumes that gas molecules behave like point masses that do not interact with one another. The pressure of the gas results from collisions of the gas molecules with the walls of the container. The contribution of one collision to the force on the wall is equal to the change in the molecule's momentum divided by the time between collisions. The magnitude of this force depends on the molecule's speed and the angle at which it strikes the wall. Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall. To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle's law in this way.

\noindent We can do a simplified derivation by making a number of assumptions. We assume that all of the molecules in a sample of gas have the same speed. Let us call it \(u\). As sketched in Figure 3, we assume that the container is a cubic box whose edge length is \(d\). If we consider all of the collisions between molecules and walls, it is clear that each wall will experience \({1}/{6}\) of the collisions; or, each pair of opposing walls will experience \({\mathrm{1}}/{\mathrm{3}}\) of the collisions. Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box. Since they are point masses, they never collide with one another. If we suppose that \({\mathrm{1}}/{\mathrm{3}}\) of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds. In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4.

\begin{figure}
\centering
\caption{Figure 3. Simplified model for velocities of gas molecules in a cubic box.}
\end{figure}

\noindent Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule's speed remains constant, but its direction changes by 180\({}^{o}\); that is, the molecule's velocity changes from \(\mathop{u}\limits^{\rightharpoonup}\) to \(-\mathop{u}\limits^{\rightharpoonup}\). Letting \(\Delta t\) be the time required for a round trip, the distance traversed in a round trip is
\begin{equation}
\begin{aligned}
2d &= \left|\mathop{u}\limits^{\rightharpoonup}\right|\Delta t \\
~ &=u\Delta t
\end{aligned}
\label{eq:round_trip_distance}
\end{equation}
The magnitude of the momentum change for a molecule in one collision is
\begin{equation}
\begin{aligned}
\left|\Delta (m\mathop{u}\limits^{\rightharpoonup})\right| &=\left|m{\mathop{u}\limits^{\rightharpoonup}}_{\text{final}}-m{\mathop{u}\limits^{\rightharpoonup}}_{\text{initial}}\right| \\
&=\left|m{\mathop{u}\limits^{\rightharpoonup}}_{\text{final}}-\left({-m\mathop{u}\limits^{\rightharpoonup}}_{\text{final}}\right)\right| \\
&=2mu
\end{aligned}
\label{eq:momentum_change}
\end{equation}
The magnitude of the force on the wall from one collision is
\begin{equation}
F=\frac{\left|\Delta \left(m\mathop{u}\limits^{\rightharpoonup}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d}
\label{eq:force_from_one_collision}
\end{equation}
and the pressure contribution from one collision on the wall, of area \(d^2\), is
\begin{equation}
P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V}
\label{eq:pressure_from_one_collision}
\end{equation}
so that we have
\begin{equation}
PV=mu^2
\label{eq:pv_relation_one_molecule}
\end{equation}
from the collision of one molecule with one wall.

\noindent If the number of molecules in the box is \(N\), \(N/3\) of them make collisions with this wall, so that the total pressure on one wall attributable to all \(N\) molecules in the box is
\begin{equation}
P=\frac{mu^2}{V}\frac{N}{3}
\label{eq:pressure_n_molecules}
\end{equation}
or
\begin{equation}
PV=\frac{Nmu^2}{3}
\label{eq:pv_relation_n_molecules}
\end{equation}
Since the ideal gas equation can be written as \(PV=NkT\) we see that \({Nmu^2}/{3}=NkT\) so that \(mu^2=3kT\) and
\begin{equation}
u=\sqrt{\frac{3kT}{m}}
\label{eq:rms_speed_molecular}
\end{equation}
Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, \(v\), can have any value between zero and---for present purposes---infinity. When we average the values of \(v^2\) for many molecules, we find the average value of the squared speeds, \(\overline{v^2}\). In Chapter 4, we find that \(u^2=\overline{v^2}\). That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, \(v_{rms}=u=\sqrt{\overline{v^2}}\).) This result also gives us the (average) kinetic energy of a single gas molecule:
\begin{equation}
KE=\frac{mu^2}{2}=\frac{3kT}{2}
\label{eq:kinetic_energy_single_molecule}
\end{equation}
From this derivation, we have a simple mechanical model that explains Boyle's law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature.\textit{.}

\noindent Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules' kinetic energy.) The energy of one mole of monatomic ideal gas molecules is
\begin{equation}
KE=\left({3}/{2}\right)RT
\label{eq:kinetic_energy_mole_ideal_gas}
\end{equation}
When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than \(\left({3}/{2}\right)RT\), because of the energy associated with these additional motions.

\noindent We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that
\begin{equation}
{\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0
\label{eq:energy_independent_volume_pressure}
\end{equation}
for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature.

\noindent While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule's early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy.

\noindent Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.)

\end{document}

[bhpayne]

No implicit references to equations found!

prompt to Gemini 2.0 Flash Thinking Experimental 01-21 https://aistudio.google.com/prompts/

The following Latex file contains a derivation with many steps. Sometimes a previous expression is referenced implicitly.

Edit the following text to manually insert references where appropriate. For example replace text like "substitute the forces" with "substitute Eq.~\ref{} to get".

Be sure to reference the relevant equation labels so that Latex can compile the document.

\documentclass{article}
\usepackage{amsmath}

% margins of 1 inch:
\setlength{\topmargin}{-.5in}
\setlength{\textheight}{9in}
\setlength{\oddsidemargin}{0in}
\setlength{\textwidth}{6.5in}

\usepackage[pdftex]{hyperref} % hyperlink equation and bibliographic citations
\author{Ben Payne, with Gemini 2.0}
\title{Boyle's Law from first principles}

\begin{document}
\maketitle
\begin{abstract}
Derive Boyle's Law using simplifications.
\end{abstract}


We can derive Boyle's law from Newtonian mechanics. This derivation assumes that gas molecules behave like point masses that do not interact with one another. The pressure of the gas results from collisions of the gas molecules with the walls of the container. The contribution of one collision to the force on the wall is equal to the change in the molecule's momentum divided by the time between collisions. The magnitude of this force depends on the molecule's speed and the angle at which it strikes the wall. Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall. To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle's law in this way.

We can do a simplified derivation by making a number of assumptions. We assume that all of the molecules in a sample of gas have the same speed. Let us call it $u$. As sketched in Figure 3, we assume that the container is a cubic box whose edge length is $d$. If we consider all of the collisions between molecules and walls, it is clear that each wall will experience ${1}/{6}$ of the collisions; or, each pair of opposing walls will experience ${\mathrm{1}}/{\mathrm{3}}$ of the collisions. Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box. Since they are point masses, they never collide with one another. If we suppose that ${\mathrm{1}}/{\mathrm{3}}$ of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds. In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4.

\begin{figure}
\centering
\caption{Figure 3. Simplified model for velocities of gas molecules in a cubic box.}
\end{figure}

Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule's speed remains constant, but its direction changes by $180^{o}$; that is, the molecule's velocity changes from $\vec{u}$ to $-\vec{u}$. Letting $\Delta t$ be the time required for a round trip, the distance traversed in a round trip is
\begin{equation}
\begin{aligned}
2d &= \left|\vec{u}\right|\Delta t \\
~ &=u\Delta t
\end{aligned}
\label{eq:round_trip_distance}
\end{equation}
The magnitude of the momentum change for a molecule in one collision is
\begin{equation}
\begin{aligned}
\left|\Delta (m\vec{u})\right| &=\left|m{\vec{u}}_{\text{final}}-m{\vec{u}}_{\text{initial}}\right| \\
&=\left|m{\vec{u}}_{\text{final}}-\left({-m\vec{u}}_{\text{final}}\right)\right| \\
&=2mu
\end{aligned}
\label{eq:momentum_change}
\end{equation}
The magnitude of the force on the wall from one collision is
\begin{equation}
F=\frac{\left|\Delta \left(m\vec{u}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d}
\label{eq:force_from_one_collision}
\end{equation}
and the pressure contribution from one collision on the wall, of area $d^2$, is
\begin{equation}
P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V}
\label{eq:pressure_from_one_collision}
\end{equation}
so that we have
\begin{equation}
PV=mu^2
\label{eq:pv_relation_one_molecule}
\end{equation}
from the collision of one molecule with one wall.

If the number of molecules in the box is $N$, $N/3$ of them make collisions with this wall, so that the total pressure on one wall attributable to all $N$ molecules in the box is
\begin{equation}
P=\frac{mu^2}{V}\frac{N}{3}
\label{eq:pressure_n_molecules}
\end{equation}
or
\begin{equation}
PV=\frac{Nmu^2}{3}
\label{eq:pv_relation_n_molecules}
\end{equation}
Since the ideal gas equation can be written as $PV=NkT$ we see that ${Nmu^2}/{3}=NkT$ so that $mu^2=3kT$ and
\begin{equation}
u=\sqrt{\frac{3kT}{m}}
\label{eq:rms_speed_molecular}
\end{equation}
Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, $v$, can have any value between zero and---for present purposes---infinity. When we average the values of $v^2$ for many molecules, we find the average value of the squared speeds, $\overline{v^2}$. In Chapter 4, we find that $u^2=\overline{v^2}$. That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, $v_{rms}=u=\sqrt{\overline{v^2}}$.) This result also gives us the (average) kinetic energy of a single gas molecule:
\begin{equation}
KE=\frac{mu^2}{2}=\frac{3kT}{2}
\label{eq:kinetic_energy_single_molecule}
\end{equation}
From this derivation, we have a simple mechanical model that explains Boyle's law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature.\textit{.}

Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules' kinetic energy.) The energy of one mole of monatomic ideal gas molecules is
\begin{equation}
KE=\left({3}/{2}\right)RT
\label{eq:kinetic_energy_mole_ideal_gas}
\end{equation}
When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than $\left({3}/{2}\right)RT$, because of the energy associated with these additional motions.

We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that
\begin{equation}
{\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0
\label{eq:energy_independent_volume_pressure}
\end{equation}
for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature.

While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule's early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy.

Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.)

\end{document}

thoughts

The user wants to add equation references in a Latex document.
I need to go through the text and identify places where an equation is referenced.
Then, I need to find the corresponding equation label and insert the reference using Eq.~\ref{label}.

Let's go through the text step by step and identify the implicit equation references.

• "The contribution of one collision to the force on the wall is equal to the change in the molecule's momentum divided by the time between collisions." This is a general statement and doesn't refer to a specific equation in the text.

• "Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall." This is also a general statement.

• "To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle's law in this way." No equation reference here.

• "As sketched in Figure 3, we assume that the container is a cubic box whose edge length is $d$." Figure reference, not equation.

• "If we consider all of the collisions between molecules and walls, it is clear that each wall will experience ${1}/{6}$ of the collisions; or, each pair of opposing walls will experience ${\mathrm{1}}/{\mathrm{3}}$ of the collisions." No equation reference.

• "Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box." No equation reference.

• "If we suppose that ${\mathrm{1}}/{\mathrm{3}}$ of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds." No equation reference.

• "In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4." No equation reference.

• "Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule's speed remains constant, but its direction changes by $180^{o}$; that is, the molecule's velocity changes from $\vec{u}$ to $-\vec{u}$." No equation reference.

• "Letting $\Delta t$ be the time required for a round trip, the distance traversed in a round trip is..." This introduces Eq.~\ref{eq:round_trip_distance}.

• "The magnitude of the momentum change for a molecule in one collision is..." This introduces Eq.~\ref{eq:momentum_change}.

• "The magnitude of the force on the wall from one collision is..." This introduces Eq.~\ref{eq:force_from_one_collision}.

• "and the pressure contribution from one collision on the wall, of area $d^2$, is..." This introduces Eq.~\ref{eq:pressure_from_one_collision}.

• "so that we have..." This introduces Eq.~\ref{eq:pv_relation_one_molecule}.

• "If the number of molecules in the box is $N$, $N/3$ of them make collisions with this wall, so that the total pressure on one wall attributable to all $N$ molecules in the box is..." This introduces Eq.~\ref{eq:pressure_n_molecules}.

• "or..." This introduces Eq.~\ref{eq:pv_relation_n_molecules}.

• "Since the ideal gas equation can be written as $PV=NkT$ we see that ${Nmu^2}/{3}=NkT$ so that $mu^2=3kT$ and..." This introduces Eq.~\ref{eq:rms_speed_molecular}.

• "Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, $v$, can have any value between zero and---for present purposes---infinity. When we average the values of $v^2$ for many molecules, we find the average value of the squared speeds, $\overline{v^2}$. In Chapter 4, we find that $u^2=\overline{v^2}$. That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, $v_{rms}=u=\sqrt{\overline{v^2}}$.) This result also gives us the (average) kinetic energy of a single gas molecule:..." This introduces Eq.~\ref{eq:kinetic_energy_single_molecule}.

• "From this derivation, we have a simple mechanical model that explains Boyle's law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature.\textit{}" No equation reference.

• "Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules' kinetic energy.) The energy of one mole of monatomic ideal gas molecules is..." This introduces Eq.~\ref{eq:kinetic_energy_mole_ideal_gas}.

• "When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than $\left({3}/{2}\right)RT$, because of the energy associated with these additional motions." No equation reference.

• "We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that..." This introduces Eq.~\ref{eq:energy_independent_volume_pressure}.

• "for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature." No equation reference.

• "While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule's early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy." No equation reference.

• "Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.)" No equation reference.

Now I need to go through the text again and insert the references.

response

LLM wrote out original Latex content with no changes.

[bhpayne]

prompt to Gemini 2.0 Flash Thinking Experimental 01-21 https://aistudio.google.com/prompts/

The following latex file contains equations and variables. Provide a list, formatted as Latex, of every unique variable and a description of that variable.

For each entry in the list include a reference to the labeled equations where each variable is used. Write out just the Latex list as your answer.

\documentclass{article}
\usepackage{amsmath}

% margins of 1 inch:
\setlength{\topmargin}{-.5in}
\setlength{\textheight}{9in}
\setlength{\oddsidemargin}{0in}
\setlength{\textwidth}{6.5in}

\usepackage[pdftex]{hyperref} % hyperlink equation and bibliographic citations
\author{Ben Payne, with Gemini 2.0}
\title{Boyle's Law from first principles}

\begin{document}
\maketitle
\begin{abstract}
Derive Boyle's Law using simplifications.
\end{abstract}


We can derive Boyle's law from Newtonian mechanics. This derivation assumes that gas molecules behave like point masses that do not interact with one another. The pressure of the gas results from collisions of the gas molecules with the walls of the container. The contribution of one collision to the force on the wall is equal to the change in the molecule's momentum divided by the time between collisions. The magnitude of this force depends on the molecule's speed and the angle at which it strikes the wall. Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall. To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle's law in this way.

We can do a simplified derivation by making a number of assumptions. We assume that all of the molecules in a sample of gas have the same speed. Let us call it $u$. As sketched in Figure 3, we assume that the container is a cubic box whose edge length is $d$. If we consider all of the collisions between molecules and walls, it is clear that each wall will experience ${1}/{6}$ of the collisions; or, each pair of opposing walls will experience ${\mathrm{1}}/{\mathrm{3}}$ of the collisions. Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box. Since they are point masses, they never collide with one another. If we suppose that ${\mathrm{1}}/{\mathrm{3}}$ of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds. In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4.

\begin{figure}
\centering
\caption{Figure 3. Simplified model for velocities of gas molecules in a cubic box.}
\end{figure}

Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule's speed remains constant, but its direction changes by $180^{o}$; that is, the molecule's velocity changes from $\vec{u}$ to $-\vec{u}$. Letting $\Delta t$ be the time required for a round trip, the distance traversed in a round trip is
\begin{equation}
\begin{aligned}
2d &= \left|\vec{u}\right|\Delta t \\
~ &=u\Delta t
\end{aligned}
\label{eq:round_trip_distance}
\end{equation}
The magnitude of the momentum change for a molecule in one collision is
\begin{equation}
\begin{aligned}
\left|\Delta (m\vec{u})\right| &=\left|m{\vec{u}}_{\text{final}}-m{\vec{u}}_{\text{initial}}\right| \\
&=\left|m{\vec{u}}_{\text{final}}-\left({-m\vec{u}}_{\text{final}}\right)\right| \\
&=2mu
\end{aligned}
\label{eq:momentum_change}
\end{equation}
The magnitude of the force on the wall from one collision is
\begin{equation}
F=\frac{\left|\Delta \left(m\vec{u}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d}
\label{eq:force_from_one_collision}
\end{equation}
and the pressure contribution from one collision on the wall, of area $d^2$, is
\begin{equation}
P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V}
\label{eq:pressure_from_one_collision}
\end{equation}
so that we have
\begin{equation}
PV=mu^2
\label{eq:pv_relation_one_molecule}
\end{equation}
from the collision of one molecule with one wall.

If the number of molecules in the box is $N$, $N/3$ of them make collisions with this wall, so that the total pressure on one wall attributable to all $N$ molecules in the box is
\begin{equation}
P=\frac{mu^2}{V}\frac{N}{3}
\label{eq:pressure_n_molecules}
\end{equation}
or
\begin{equation}
PV=\frac{Nmu^2}{3}
\label{eq:pv_relation_n_molecules}
\end{equation}
Since the ideal gas equation can be written as $PV=NkT$ we see that ${Nmu^2}/{3}=NkT$ so that $mu^2=3kT$ and
\begin{equation}
u=\sqrt{\frac{3kT}{m}}
\label{eq:rms_speed_molecular}
\end{equation}
Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, $v$, can have any value between zero and---for present purposes---infinity. When we average the values of $v^2$ for many molecules, we find the average value of the squared speeds, $\overline{v^2}$. In Chapter 4, we find that $u^2=\overline{v^2}$. That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, $v_{rms}=u=\sqrt{\overline{v^2}}$.) This result also gives us the (average) kinetic energy of a single gas molecule:
\begin{equation}
KE=\frac{mu^2}{2}=\frac{3kT}{2}
\label{eq:kinetic_energy_single_molecule}
\end{equation}
From this derivation, we have a simple mechanical model that explains Boyle's law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature.\textit{.}

Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules' kinetic energy.) The energy of one mole of monatomic ideal gas molecules is
\begin{equation}
KE=\left({3}/{2}\right)RT
\label{eq:kinetic_energy_mole_ideal_gas}
\end{equation}
When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than $\left({3}/{2}\right)RT$, because of the energy associated with these additional motions.

We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that
\begin{equation}
{\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0
\label{eq:energy_independent_volume_pressure}
\end{equation}
for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature.

While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule's early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy.

Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.)

\end{document}

thoughts

The user wants a Latex formatted list of all unique variables in the provided Latex document, along with a description for each variable and references to the equation labels where they are used.

Here's a plan:

1. Identify all variables: Go through the Latex document and identify every variable used in equations and text descriptions.
2. Find unique variables: Create a list of unique variables from the identified variables.
3. Write descriptions: For each unique variable, write a concise description based on the context in the document.
4. Find equation references: For each unique variable, find all labeled equations where it is used.
5. Format in Latex: Construct a Latex list with each variable, its description, and equation references, as requested by the user.

Let's go through the document and identify variables:

• $u$: speed of molecules (introduced before equation \eqref{eq:round_trip_distance})
• $d$: edge length of cubic box (introduced before equation \eqref{eq:round_trip_distance})
• $\Delta t$: time for a round trip (equation \eqref{eq:round_trip_distance})
• $\vec{u}$: velocity of a molecule (equation \eqref{eq:round_trip_distance})
• $m$: mass of a molecule (equation \eqref{eq:momentum_change})
• $\Delta (m\vec{u})$: change in momentum (equation \eqref{eq:momentum_change})
• $F$: force (equation \eqref{eq:force_from_one_collision})
• $P$: pressure (equation \eqref{eq:pressure_from_one_collision})
• $A$: area (equation \eqref{eq:pressure_from_one_collision}) - in this context, it's $d^2$
• $V$: volume (equation \eqref{eq:pressure_from_one_collision}) - in this context, it's $d^3$
• $N$: number of molecules (equation \eqref{eq:pressure_n_molecules})
• $k$: Boltzmann constant (equation \eqref{eq:pv_relation_n_molecules} and \eqref{eq:rms_speed_molecular})
• $T$: temperature (equation \eqref{eq:pv_relation_n_molecules} and \eqref{eq:rms_speed_molecular})
• $KE$: kinetic energy (equation \eqref{eq:kinetic_energy_single_molecule} and \eqref{eq:kinetic_energy_mole_ideal_gas})
• $R$: ideal gas constant (equation \eqref{eq:kinetic_energy_mole_ideal_gas})
• $E$: energy (equation \eqref{eq:energy_independent_volume_pressure})

Unique variables are: $u, d, \Delta t, \vec{u}, m, F, P, A, V, N, k, T, KE, R, E$.
Let's write descriptions and find equation references for each:

• $u$: speed of a molecule. Equations: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}.
• $d$: edge length of the cubic box. Equations: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}.
• $\Delta t$: time for a round trip of a molecule between opposite walls. Equations: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}.
• $\vec{u}$: velocity of a molecule. Equations: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}.
• $m$: mass of a molecule. Equations: \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}.
• $F$: magnitude of the force on the wall from one collision. Equations: \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}.
• $P$: pressure. Equations: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}.
• $A$: area of the wall. Equation: \eqref{eq:pressure_from_one_collision}.
• $V$: volume of the cubic box. Equations: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}.
• $N$: number of molecules in the box. Equations: \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}.
• $k$: Boltzmann constant. Equations: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}.
• $T$: temperature. Equations: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}, \eqref{eq:energy_independent_volume_pressure}.
• $KE$: kinetic energy of a molecule or mole of gas. Equations: \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}.
• $R$: ideal gas constant. Equation: \eqref{eq:kinetic_energy_mole_ideal_gas}.
• $E$: energy of an ideal gas. Equation: \eqref{eq:energy_independent_volume_pressure}.

Now, format the list in Latex:

\begin{itemize}
    \item $A$: Area of the wall. Ref: \eqref{eq:pressure_from_one_collision}
    \item $d$: Edge length of the cubic box. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $\Delta t$: Time for a round trip of a molecule between opposite walls. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}
    \item $E$: Energy of an ideal gas. Ref: \eqref{eq:energy_independent_volume_pressure}
    \item $F$: Magnitude of the force on the wall from one collision. Ref: \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $k$: Boltzmann constant. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $KE$: Kinetic energy of a molecule or mole of gas. Ref: \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $m$: Mass of a molecule. Ref: \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $N$: Number of molecules in the box. Ref: \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}
    \item $P$: Pressure. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
    \item $R$: Ideal gas constant. Ref: \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $T$: Temperature. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}, \eqref{eq:energy_independent_volume_pressure}
    \item $u$: Speed of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $\vec{u}$: Velocity of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}
    \item $V$: Volume of the cubic box. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
\end{itemize}

Double check: all unique variables are there with descriptions and equation references. The format is correct.

response

\begin{itemize}
    \item $A$: Area of the wall. Ref: \eqref{eq:pressure_from_one_collision}
    \item $d$: Edge length of the cubic box. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $\Delta t$: Time for a round trip of a molecule between opposite walls. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}
    \item $E$: Energy of an ideal gas. Ref: \eqref{eq:energy_independent_volume_pressure}
    \item $F$: Magnitude of the force on the wall from one collision. Ref: \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $k$: Boltzmann constant. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $KE$: Kinetic energy of a molecule or mole of gas. Ref: \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $m$: Mass of a molecule. Ref: \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $N$: Number of molecules in the box. Ref: \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}
    \item $P$: Pressure. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
    \item $R$: Ideal gas constant. Ref: \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $T$: Temperature. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}, \eqref{eq:energy_independent_volume_pressure}
    \item $u$: Speed of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $\vec{u}$: Velocity of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}
    \item $V$: Volume of the cubic box. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
\end{itemize}

[bhpayne]

Latex file is now

\documentclass{article}
\usepackage{amsmath}

% margins of 1 inch:
\setlength{\topmargin}{-.5in}
\setlength{\textheight}{9in}
\setlength{\oddsidemargin}{0in}
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\usepackage[pdftex]{hyperref} % hyperlink equation and bibliographic citations
\author{Ben Payne, with Gemini 2.0}
\title{Boyle's Law from first principles}

\begin{document}
\maketitle
\begin{abstract}
Derive Boyle's Law using simplifications.
\end{abstract}

\section{Variables used in Derivation}

\begin{itemize}
    \item $A$: Area of the wall. Ref: \eqref{eq:pressure_from_one_collision}
    \item $d$: Edge length of the cubic box. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $\Delta t$: Time for a round trip of a molecule between opposite walls. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:force_from_one_collision}
    \item $E$: Energy of an ideal gas. Ref: \eqref{eq:energy_independent_volume_pressure}
    \item $F$: Magnitude of the force on the wall from one collision. Ref: \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}
    \item $k$: Boltzmann constant. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $KE$: Kinetic energy of a molecule or mole of gas. Ref: \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $m$: Mass of a molecule. Ref: \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $N$: Number of molecules in the box. Ref: \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}
    \item $P$: Pressure. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
    \item $R$: Ideal gas constant. Ref: \eqref{eq:kinetic_energy_mole_ideal_gas}
    \item $T$: Temperature. Ref: \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}, \eqref{eq:kinetic_energy_mole_ideal_gas}, \eqref{eq:energy_independent_volume_pressure}
    \item $u$: Speed of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}, \eqref{eq:force_from_one_collision}, \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:rms_speed_molecular}, \eqref{eq:kinetic_energy_single_molecule}
    \item $\vec{u}$: Velocity of a molecule. Ref: \eqref{eq:round_trip_distance}, \eqref{eq:momentum_change}
    \item $V$: Volume of the cubic box. Ref: \eqref{eq:pressure_from_one_collision}, \eqref{eq:pv_relation_one_molecule}, \eqref{eq:pressure_n_molecules}, \eqref{eq:pv_relation_n_molecules}, \eqref{eq:energy_independent_volume_pressure}
\end{itemize}


\section{Introduction}
We can derive Boyle's law from Newtonian mechanics. This derivation assumes that gas molecules behave like point masses that do not interact with one another. The pressure of the gas results from collisions of the gas molecules with the walls of the container. The contribution of one collision to the force on the wall is equal to the change in the molecule's momentum divided by the time between collisions. The magnitude of this force depends on the molecule's speed and the angle at which it strikes the wall. Each such collision makes a contribution to the pressure that is equal to the force divided by the area of the wall. To find the pressure from this model, it is necessary to average over all possible molecular speeds and all possible collision angles. In Chapter 4, we derive Boyle's law in this way.

We can do a simplified derivation by making a number of assumptions. We assume that all of the molecules in a sample of gas have the same speed. Let us call it $u$. As sketched in Figure 3, we assume that the container is a cubic box whose edge length is $d$. If we consider all of the collisions between molecules and walls, it is clear that each wall will experience ${1}/{6}$ of the collisions; or, each pair of opposing walls will experience ${\mathrm{1}}/{\mathrm{3}}$ of the collisions. Instead of averaging over all of the possible angles at which a molecule could strike a wall and all of the possible times between collisions, we assume that the molecules travel at constant speed back and forth between opposite faces of the box. Since they are point masses, they never collide with one another. If we suppose that ${\mathrm{1}}/{\mathrm{3}}$ of the molecules go back and forth between each pair of opposite walls, we can expect to accomplish the same kind of averaging in setting up our artificial model that we achieve by averaging over the real distribution of angles and speeds. In fact, this turns out to be the case; the derivation below gets the same result as the rigorous treatment we develop in Chapter 4.

\begin{figure}
\centering
\caption{Figure 3. Simplified model for velocities of gas molecules in a cubic box.}
\end{figure}

Since each molecule goes back and forth between opposite walls, it collides with each wall once during each round trip. At each collision, the molecule's speed remains constant, but its direction changes by $180^{o}$; that is, the molecule's velocity changes from $\vec{u}$ to $-\vec{u}$. Letting $\Delta t$ be the time required for a round trip, the distance traversed in a round trip is
\begin{equation}
\begin{aligned}
2d &= \left|\vec{u}\right|\Delta t \\
~ &=u\Delta t
\end{aligned}
\label{eq:round_trip_distance}
\end{equation}
The magnitude of the momentum change for a molecule in one collision is
\begin{equation}
\begin{aligned}
\left|\Delta (m\vec{u})\right| &=\left|m{\vec{u}}_{\text{final}}-m{\vec{u}}_{\text{initial}}\right| \\
&=\left|m{\vec{u}}_{\text{final}}-\left({-m\vec{u}}_{\text{final}}\right)\right| \\
&=2mu
\end{aligned}
\label{eq:momentum_change}
\end{equation}
The magnitude of the force on the wall from one collision is
\begin{equation}
F=\frac{\left|\Delta \left(m\vec{u}\right)\right|}{\Delta t}=\frac{2mu}{\left({2d}/{u}\right)}=\frac{mu^2}{d}
\label{eq:force_from_one_collision}
\end{equation}
and the pressure contribution from one collision on the wall, of area $d^2$, is
\begin{equation}
P=\frac{F}{A}=\frac{mu^2}{d\bullet d^2}=\frac{{mu}^2}{d^3}=\frac{{mu}^2}{V}
\label{eq:pressure_from_one_collision}
\end{equation}
so that we have
\begin{equation}
PV=mu^2
\label{eq:pv_relation_one_molecule}
\end{equation}
from the collision of one molecule with one wall.

If the number of molecules in the box is $N$, $N/3$ of them make collisions with this wall, so that the total pressure on one wall attributable to all $N$ molecules in the box is
\begin{equation}
P=\frac{mu^2}{V}\frac{N}{3}
\label{eq:pressure_n_molecules}
\end{equation}
or
\begin{equation}
PV=\frac{Nmu^2}{3}
\label{eq:pv_relation_n_molecules}
\end{equation}
Since the ideal gas equation can be written as $PV=NkT$ we see that ${Nmu^2}/{3}=NkT$ so that $mu^2=3kT$ and
\begin{equation}
u=\sqrt{\frac{3kT}{m}}
\label{eq:rms_speed_molecular}
\end{equation}
Thus we have found a relationship between the molecular speed and the temperature of the gas. (The actual speed of a molecule, $v$, can have any value between zero and---for present purposes---infinity. When we average the values of $v^2$ for many molecules, we find the average value of the squared speeds, $\overline{v^2}$. In Chapter 4, we find that $u^2=\overline{v^2}$. That is, the average speed we use in our derivation turns out to be a quantity called the root-mean-square speed, $v_{rms}=u=\sqrt{\overline{v^2}}$.) This result also gives us the (average) kinetic energy of a single gas molecule:
\begin{equation}
KE=\frac{mu^2}{2}=\frac{3kT}{2}
\label{eq:kinetic_energy_single_molecule}
\end{equation}
From this derivation, we have a simple mechanical model that explains Boyle's law as the logical consequence of point-mass molecules colliding with the walls of their container. By combining this result with the ideal gas equation, we find that the average speed of ideal gas molecules depends only on the temperature. From this we have the very important result that the translational kinetic energy of an ideal gas depends only on temperature.\textit{.}

Since our non-interacting point-mass molecules have no potential energy arising from their interactions with one another, their translational kinetic energy is the whole of their energy. (Because two such molecules neither attract nor repel one another, no work is required to change the distance between them. The work associated with changing the volume of a confined sample of an ideal gas arises because of the pressure the molecules exert on the walls of the container; the pressure arises because of the molecules' kinetic energy.) The energy of one mole of monatomic ideal gas molecules is
\begin{equation}
KE=\left({3}/{2}\right)RT
\label{eq:kinetic_energy_mole_ideal_gas}
\end{equation}
When we expand our concept of ideal gases to include molecules that have rotational or vibrational energy, but which neither attract nor repel one another, it remains true that the energy of a macroscopic sample depends only on temperature. However, the molar energy of such a gas is greater than $\left({3}/{2}\right)RT$, because of the energy associated with these additional motions.

We make extensive use of the conclusion that the energy of an ideal gas depends only on temperature. As it turns out, this conclusion follows rigorously from the second law of thermodynamics. In Chapter 10, we show that
\begin{equation}
{\left(\frac{\partial E}{\partial V}\right)}_T={\left(\frac{\partial E}{\partial P}\right)}_T=0
\label{eq:energy_independent_volume_pressure}
\end{equation}
for a substance that obeys the ideal gas equation; at constant temperature, the energy of an ideal gas is independent of the volume and independent of the pressure. So long as pressure, volume, and temperature are the only variables needed to specify its state, the laws of thermodynamics imply that the energy of an ideal gas depends only on temperature.

While the energy of an ideal gas is independent of pressure, the energy of a real gas is a function of pressure at a given temperature. At ordinary pressures and temperatures, this dependence is weak and can often be neglected. The first experimental investigation of this issue was made by James Prescott Joule, for whom the SI unit of energy is named. Beginning in 1838, Joule did a long series of careful measurements of the mechanical equivalent of heat. These measurements formed the original experimental basis for the kinetic theory of heat. Among Joule's early experiments was an attempt to measure the heat absorbed by a gas as it expanded into an evacuated container, a process known as a free expansion. No absorption of heat was observed, which implied that the energy of the gas was unaffected by the volume change. However, it is difficult to do this experiment with meaningful accuracy.

Subsequently, Joule collaborated with William Thomson (Lord Kelvin) on a somewhat different experimental approach to essentially the same question. The Joule-Thomson experiment provides a much more sensitive measure of the effects of intermolecular forces of attraction and repulsion on the energy of a gas during its expansion. Since our definition of an ideal gas includes the stipulation that there are no intermolecular forces, the Joule-Thomson experiment is consistent with the conclusion that the energy of an ideal gas depends only on temperature. However, since intermolecular forces are not zero for any real gas, our analysis reaches this conclusion in a somewhat indirect way. The complication arises because the Joule-Thomson results are not entirely consistent with the idea that all properties of a real gas approach those of an ideal gas at a sufficiently low pressure. (The best of models can have limitations.)

\end{document}

[bhpayne]

prompt to Gemini 2.0 Flash Thinking Experimental 01-21 https://aistudio.google.com/prompts/

thoughts

response