Skip to content

derivation: chemistry: Half-Life Formula for Zero-Order Reactions #89

@bhpayne

Description

@bhpayne

From https://www.google.com/search?q=Derivation+of+Half-Life+Formula+for+Zero-Order+Reactions

To derive the half-life formula for a zero-order reaction, we start with the integrated rate law for a zero-order reaction, which is: [A] = [A]₀ - kt; then, substitute [A] = [A]₀/2 (since at half-life, the concentration is halved) and solve for t (which becomes t₁/₂): [1, 2, 3]

• Start with the zero-order rate law: [1, 3, 4]
• [A] = [A]₀ - kt [1, 3, 4]

• Substitute [A] with [A]₀/2 for half-life: [1, 3, 5]
• [A]₀/2 = [A]₀ - kt₁/₂ [1, 3, 5]

• Rearrange to solve for t₁/₂: [1, 3, 4]
• kt₁/₂ = [A]₀ - [A]₀/2 [1, 3, 4]
• kt₁/₂ = [A]₀/2 [1, 3, 6]

• Isolate t₁/₂: [1, 7, 8]
• t₁/₂ = [A]₀ / (2k) [1, 7, 8]

Therefore, the half-life formula for a zero-order reaction is: t₁/₂ = [A]₀ / (2k), where [A]₀ is the initial concentration and k is the rate constant. [1, 7, 8]
Key points to remember: [2, 3, 9]

• In a zero-order reaction, the rate is independent of the reactant concentration, meaning the rate remains constant throughout the reaction. [2, 3, 9]
• The half-life of a zero-order reaction is directly proportional to the initial concentration. [5, 7, 8, 10, 11]
• This means that as the initial concentration increases, the half-life also increases. [5, 7, 8]

Metadata

Metadata

Assignees

Labels

No labels
No labels

Type

No type

Projects

Status

derivations backlog

Milestone

No milestone

Relationships

None yet

Development

No branches or pull requests

Issue actions