[Unity] Ignore R.ExternFunc in EliminateCommonSubexpr#15900
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Hzfengsy merged 1 commit intoapache:unityfrom Oct 11, 2023
Merged
[Unity] Ignore R.ExternFunc in EliminateCommonSubexpr#15900Hzfengsy merged 1 commit intoapache:unityfrom
Hzfengsy merged 1 commit intoapache:unityfrom
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Prior to this commit, `relax::ExternFunc` nodes would be de-duplicated as part of the `EliminateCommonSubexpr` pass. This commit instead ignores the `relax::ExternFunc` nodes, retaining the in-line definitions.
| @R.function(pure=False) | ||
| def foo(x: R.Tensor((2, 3), dtype="float32")): | ||
| y = R.call_packed("extern_func_name", x, sinfo_args=R.Tensor([2, 3])) | ||
| z = R.call_packed("extern_func_name", y, sinfo_args=R.Tensor([2, 3])) |
Contributor
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If this was commoned before, then something else is probably wrong. This is equivalent to extern_func(extern_func(x)), so there is no opportunity to common anything even if the external function was known to be pure.
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Previously, it wasn't a computational step that was being extracted as the common subexpression, but the R.ExternFunc object itself.
@I.ir_module
class Module:
@R.function(pure=False)
def foo(x: R.Tensor((2, 3), dtype="float32")):
gv = R.ExternFunc("extern_func_name")
y = gv(x, sinfo_args=(R.Tensor((2, 3)),))
z = gv(y, sinfo_args=(R.Tensor((2, 3)),))
return z
Contributor
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I see. Yeah, that seems unnecessary.
kparzysz-quic
approved these changes
Oct 9, 2023
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Prior to this commit,
relax::ExternFuncnodes would be de-duplicated as part of theEliminateCommonSubexprpass. This commit instead ignores therelax::ExternFuncnodes, retaining the in-line definitions.