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Solution: Isaura Martí #37

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Solution: Isaura Martí #37

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7be3377
exercise mysql-basics
imarti01 Jan 24, 2023
11e4b52
fix select
imarti01 Jan 24, 2023
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108 changes: 108 additions & 0 deletions employees.sql
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-- Sample employee database
-- See changelog table for details
-- Copyright (C) 2007,2008, MySQL AB
--
-- Original data created by Fusheng Wang and Carlo Zaniolo
-- http://www.cs.aau.dk/TimeCenter/software.htm
-- http://www.cs.aau.dk/TimeCenter/Data/employeeTemporalDataSet.zip
--
-- Current schema by Giuseppe Maxia
-- Data conversion from XML to relational by Patrick Crews
--
-- This work is licensed under the
-- Creative Commons Attribution-Share Alike 3.0 Unported License.
-- To view a copy of this license, visit
-- http://creativecommons.org/licenses/by-sa/3.0/ or send a letter to
-- Creative Commons, 171 Second Street, Suite 300, San Francisco,
-- California, 94105, USA.
--
-- DISCLAIMER
-- To the best of our knowledge, this data is fabricated, and
-- it does not correspond to real people.
-- Any similarity to existing people is purely coincidental.
--

DROP DATABASE IF EXISTS employees;
CREATE DATABASE IF NOT EXISTS employees;
USE employees;

SELECT 'CREATING DATABASE STRUCTURE' as 'INFO';

DROP TABLE IF EXISTS dept_emp,
dept_manager,
titles,
salaries,
employees,
departments;

/*!50503 set default_storage_engine = InnoDB */;
/*!50503 select CONCAT('storage engine: ', @@default_storage_engine) as INFO */;

CREATE TABLE employees (
emp_no INT NOT NULL,
birth_date DATE NOT NULL,
first_name VARCHAR(14) NOT NULL,
last_name VARCHAR(16) NOT NULL,
gender ENUM ('M','F') NOT NULL,
hire_date DATE NOT NULL,
PRIMARY KEY (emp_no)
);

CREATE TABLE departments (
dept_no CHAR(4) NOT NULL,
dept_name VARCHAR(40) NOT NULL,
PRIMARY KEY (dept_no),
UNIQUE KEY (dept_name)
);

CREATE TABLE dept_manager (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE dept_emp (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE titles (
emp_no INT NOT NULL,
title VARCHAR(50) NOT NULL,
from_date DATE NOT NULL,
to_date DATE,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,title, from_date)
)
;

CREATE TABLE salaries (
emp_no INT NOT NULL,
salary INT NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no, from_date)
)
;

CREATE OR REPLACE VIEW dept_emp_latest_date AS
SELECT emp_no, MAX(from_date) AS from_date, MAX(to_date) AS to_date
FROM dept_emp
GROUP BY emp_no;

# shows only the current department for each employee
CREATE OR REPLACE VIEW current_dept_emp AS
SELECT l.emp_no, dept_no, l.from_date, l.to_date
FROM dept_emp d
INNER JOIN dept_emp_latest_date l
ON d.emp_no=l.emp_no AND d.from_date=l.from_date AND l.to_date = d.to_date;
267 changes: 267 additions & 0 deletions queries.sql
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-- INSERT DATA

-- At least 15 employees (at least 3 with same name)

INSERT INTO employees VALUES
(1, "1990-12-03", "Laia", "Estruch", "F", "2015-07-14"),
(2, "1985-08-20", "Guillem", "Sala", "M", "2015-07-14"),
(3, "1980-03-23", "Laura", "Romià", "F", "2016-04-20"),
(4, "1989-04-10", "Aleix", "Pons", "M", "2016-07-30"),
(5, "1970-02-21", "Paula", "Gual", "F", "2017-01-24"),
(6, "1973-03-30", "Laia", "Mas", "F", "2018-01-15"),
(7, "1984-09-29", "Xavi", "Ros", "M", "2018-03-12"),
(8, "1985-11-21", "Blai", "Vives", "M", "2018-07-15"),
(9, "1983-12-12", "Laia", "Llach", "F", "2019-01-24"),
(10, "1989-08-19", "Joan", "Soler", "M", "2020-05-05"),
(11, "1985-07-25", "Ares", "Nadal", "F", "2020-05-05"),
(12, "1990-06-28", "Arnau", "Roig", "M", "2021-07-02"),
(13, "1994-07-12", "Rita", "Pitarch", "F", "2021-08-30"),
(14, "1995-10-21", "Xavi", "Vidal", "M", "2021-09-20"),
(15, "1984-12-11", "Marta", "Grau", "F", "2022-07-24");

-- Salaries between 5000 and 50000 of different gender
-- 5 employees must have at least two salaries in different ranges of dates and different amounts

INSERT INTO salaries VALUES
(1, 15000, "2015-07-14", "2016-07-14"),
(1, 45000, "2016-07-14", "2019-07-14"),
(1, 37000, "2019-07-14", "2022-12-31"),
(2, 25000, "2015-07-14", "2017-07-14"),
(2, 35000, "2017-07-14", "2019-08-30"),
(2, 35000, "2019-08-31", "2022-12-31"),
(3, 45000, "2016-04-20", "2020-12-31"),
(3, 50000, "2021-01-01", "2022-12-31"),
(4, 37000, "2016-07-30", "2020-12-31"),
(4, 39000, "2021-01-01", "2022-12-31"),
(5, 37000, "2017-01-24", "2020-12-31"),
(5, 39000, "2021-01-01", "2022-12-31"),
(6, 26000, "2018-01-15", "2020-12-31"),
(6, 32000, "2021-01-01", "2022-12-31"),
(7, 27000, "2018-03-12", "2020-12-31"),
(7, 29000, "2021-01-01", "2022-12-31"),
(8, 50000, "2018-07-15", "2022-12-31"),
(9, 42000, "2019-01-24", "2022-12-31"),
(10, 36000, "2020-05-05", "2022-12-31"),
(11, 36000, "2020-05-05", "2022-12-31"),
(12, 24000, "2021-07-02", "2022-12-31"),
(13, 22000, "2021-08-30", "2022-12-31"),
(14, 19000, "2021-09-20", "2022-12-31"),
(15, 8000, "2022-07-24", "2022-12-31");

-- 10 employees belong to more than one department

INSERT INTO departments VALUES
("FNNC", "Finance"),
("CCNT", "Accounting"),
("MRKT", "Marketing"),
("RSRC", "Research"),
("DVLP", "Development"),
("HMNR", "Human Resources"),
("PRDC", "Production");

INSERT INTO dept_emp VALUES
(5, "HMNR", "2017-01-24", "2023-01-20"),
(5, "FNNC", "2017-01-24", "2023-01-20"),
(7, "FNNC", "2018-03-12", "2023-01-20"),
(7, "CCNT", "2018-03-12", "2023-01-20"),
(8, "PRDC", "2018-07-15", "2023-01-20"),
(9, "PRDC", "2019-01-24", "2023-01-20"),
(9, "MRKT", "2019-01-24", "2023-01-20"),
(10, "HMNR", "2020-05-05", "2023-01-20"),
(10, "MRKT", "2022-05-01", "2023-01-20"),
(11, "DVLP", "2020-05-05", "2023-01-20"),
(11, "RSRC", "2021-01-01", "2023-01-20"),
(12, "PRDC", "2021-07-02", "2023-01-20"),
(12, "RSRC", "2022-01-01", "2023-01-20"),
(13, "PRDC", "2021-08-30", "2023-01-20"),
(14, "PRDC", "2021-09-20", "2023-01-20"),
(15, "CCNT", "2022-07-24", "2023-01-20"),
(15, "PRDC", "2022-07-24", "2023-01-20");

-- 5 employees are managers

INSERT INTO dept_manager VALUES
(1, "FNNC", "2020-01-01", "2023-01-20"),
(1, "CCNT", "2020-01-01", "2023-01-20"),
(3, "MRKT", "2018-05-15", "2023-01-20"),
(2, "RSRC", "2018-12-14", "2023-01-20"),
(2, "DVLP", "2018-12-14", "2023-01-20"),
(4, "HMNR", "2018-07-30", "2023-01-20"),
(6, "PRDC", "2019-03-24", "2023-01-20");

-- All employees have a degree and at least 5 titles are from 2020

INSERT INTO titles VALUES
(1, "Finance and Accounting Degree", "2010-02-15", "2015-02-15"),
(2, "Research and Development Degree", "2010-09-15", "2015-06-15"),
(3, "Marketing Degree", "2010-09-15", "2015-06-15"),
(4, "Human Resources Degree", "2011-02-15", "2016-02-15"),
(5, "Finance and Accounting Degree", "2011-09-15", "2016-06-15"),
(6, "Production Degree", "2012-09-15", "2017-06-15"),
(7, "Finance and Accounting Degree", "2012-09-15", "2017-06-15"),
(8, "Production Degree", "2013-09-15", "2018-06-15"),
(9, "Marketing Degree", "2013-02-15", "2018-02-15"),
(10, "Human Resources Degree", "2015-02-15", "2020-02-15"),
(11, "Research and Development Degree", "2015-02-15", "2020-02-15"),
(12, "Production Degree", "2015-09-15", "2020-06-15"),
(13, "Production Degree", "2015-09-15", "2020-06-15"),
(14, "Production Degree", "2015-09-15", "2020-06-15"),
(15, "Accounting Degree", "2015-09-15", "2020-06-15");

-- UPDATE DATA

-- UPDATE EMPLOYEES _ Change name of an employee (query based on name, surname and date of birth)

UPDATE employees
SET first_name = "Lara"
WHERE first_name = "Laura" AND last_name = "Romi?" AND birth_date = "1980-03-23";

-- UPDATE DEPARTMENTS _ Change the name of all departments

UPDATE departments SET dept_name = CONCAT(dept_name, " Dpt");

-- GET DATA
-- Select all employees with a salary greater than 20,000, you must list all employees data and the salary.

SELECT employees.*, salaries.salary FROM employees
LEFT JOIN salaries ON employees.emp_no = salaries.emp_no
WHERE salaries.salary > 20000;

-- Select all employees with a salary below 10,000, you must list all employees data and the salary.

SELECT employees.*, salaries.salary FROM employees
LEFT JOIN salaries ON employees.emp_no = salaries.emp_no
WHERE salaries.salary < 10000;

-- Select all employees who have a salary between 14,000 and 50,000, you must list all employees data and the salary.

SELECT employees.*, salaries.salary FROM employees
LEFT JOIN salaries ON employees.emp_no = salaries.emp_no
WHERE salaries.salary > 14000 AND salaries.salary < 50000;

-- Select the total number of employees

SELECT COUNT(emp_no) FROM employees;

-- Select the total number of employees who have worked in more than one department

SELECT COUNT(*) FROM
( SELECT emp_no, COUNT(*) AS CNT
FROM dept_emp
GROUP BY emp_no
) AS T
WHERE CNT > 1;

-- Select the titles of the year 2020

SELECT title FROM titles WHERE to_date LIKE "2020%";

-- Select the name of all employees with capital letters

SELECT UPPER(first_name) FROM employees;

-- Select the name, surname and name of the current department of each employee

SELECT T.first_name, T.last_name, departments.dept_name FROM
(SELECT first_name, last_name, dept_no FROM employees
INNER JOIN dept_emp ON employees.emp_no = dept_emp.emp_no) AS T
INNER JOIN departments ON T.dept_no = departments.dept_no;

-- Select the name, surname and number of times the employee has worked as a manager

SELECT first_name, last_name, COUNT(*) AS CNT FROM employees
INNER JOIN dept_manager ON employees.emp_no = dept_manager.emp_no
GROUP BY employees.emp_no;

-- Select the name of employees without any being repeated

SELECT DISTINCT first_name FROM employees;

-- DELETE DATA

-- Delete all employees with a salary greater than 20,000

DELETE employees FROM employees
INNER JOIN salaries ON employees.emp_no = salaries.emp_no
WHERE salaries.salary > 20000;

-- Remove the department that has more employees.

DELETE FROM departments
WHERE dept_no = (SELECT dept_no FROM dept_emp GROUP BY dept_no ORDER BY COUNT(dept_no) DESC LIMIT 1);

-- Case more than one department to delete.

DELETE FROM departments
WHERE dept_no IN (SELECT T.dept_no FROM
(SELECT dept_no, COUNT(dept_no) AS num_limit FROM dept_emp
GROUP BY dept_no) AS T
WHERE T.num_limit = (SELECT COUNT(dept_no) AS num_limit FROM dept_emp
GROUP BY dept_no ORDER BY num_limit DESC LIMIT 1));


-- DESIGN AND CREATE A DATABASE

DROP DATABASE IF EXISTS gym;
CREATE DATABASE IF NOT EXISTS gym;
USE gym;

SELECT 'CREATING DATABASE STRUCTURE' as 'INFO';

DROP TABLE IF EXISTS rates,
users,
user_bracelet,
trainers,
activities,
activity_room;

CREATE TABLE rates (
id_rate CHAR(4) NOT NULL,
name_rate TEXT(15) NOT NULL,
price FLOAT(4) NOT NULL,
PRIMARY KEY (id_rate)
);

CREATE TABLE users (
id_user INT NOT NULL AUTO_INCREMENT,
full_name TEXT(50) NOT NULL,
phone VARCHAR(12) NOT NULL,
email VARCHAR(30) NOT NULL,
id_rate CHAR(4) NOT NULL,
PRIMARY KEY (id_user),
FOREIGN KEY (id_rate) REFERENCES rates (id_rate) ON DELETE CASCADE
);

CREATE TABLE user_bracelet (
bracelet_num INT(10) NOT NULL AUTO_INCREMENT,
id_user INT NOT NULL,
PRIMARY KEY (bracelet_num),
FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE CASCADE
);

CREATE TABLE trainers (
id_trainer INT(2) NOT NULL AUTO_INCREMENT,
full_name TEXT(50) NOT NULL,
PRIMARY KEY (id_trainer)
);

CREATE TABLE activity_room (
id_room VARCHAR(5) NOT NULL,
name_room VARCHAR(20) NOT NULL,
PRIMARY KEY (id_room)
);

CREATE TABLE activities (
id_activity CHAR(4) NOT NULL,
name_activity VARCHAR(40) NOT NULL,
id_room VARCHAR(5) NOT NULL,
id_trainer INT(2) NOT NULL,
id_user INT NOT NULL,
PRIMARY KEY (id_activity),
FOREIGN KEY (id_room) REFERENCES activity_room (id_room) ON DELETE CASCADE,
FOREIGN KEY (id_trainer) REFERENCES trainers (id_trainer) ON DELETE CASCADE,
FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE CASCADE
);