🐞 bug report
Affected Rule
python.runfiles Rlocation()
Is this a regression?
No
Description
When we call Rlocation() inside of a custom python package without passing in the source_repo= parameter and import our package for use elsewhere, if sys.path includes a path to our package's code that is outside the runfiles directory, then the Rlocation() call will fail.
Specifically, this is caused by the code here, which attempts to look up runfiles using the repository mapping of the caller of the Rlocation() method. If sys.path has found and run the copy of our python package that resides outside of the runfiles directory, then the Rlocation() call is legitimately coming from outside the runfiles directory, causing the underlying call to self.CurrentRepository() to fail.
A custom package which calls Rlocation() shouldn't be required to provide the source_repo= parameter or else run the risk of error due to being found outside of the runfiles directory due to the configuration of sys.path.
🔬 Minimal Reproduction
MODULE.bazel
module(name = "reproducer")
bazel_dep(
name = "rules_python",
version = "1.9.0"
)
python = use_extension("@rules_python//python/extensions:python.bzl", "python")
python.toolchain(
python_version = "3.14",
)
BUILD.bazel
load("@rules_python//python:py_binary.bzl", "py_binary")
load("@rules_python//python:py_library.bzl", "py_library")
py_binary(
name = "binary",
srcs = ["binary.py"],
deps = [":library"],
visibility = ["//visibility:public"],
)
py_library(
name = "library",
srcs = ["library/__init__.py"],
deps = ["@rules_python//python/runfiles"],
visibility = ["//visibility:public"],
)
binary.py
from library import rlocation_wrapper
if __name__ == "__main__":
rlocation_wrapper()
library/__init__.py
from python.runfiles import Runfiles
def rlocation_wrapper() -> None:
runfiles_obj = Runfiles.Create()
print(runfiles_obj.Rlocation("library/__init__"))
In order to have sys.path find the package outside the runfiles directory, we can set the PYTHONPATH environment variable to the outer folder containing the package.
To reproduce the failure, run:
export PYTHONPATH=/home/<username>/<reproduction_folder>
bazelisk run //:binary
🔥 Exception or Error
ValueError: /home/<username>/<reproduction_folder>/library/__init__.py does not lie under the runfiles root /home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles
Full traceback:
Traceback (most recent call last):
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/_main/_binary_stage2_bootstrap.py", line 537, in <module>
main()
~~~~^^
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/_main/_binary_stage2_bootstrap.py", line 531, in main
_run_py_path(main_filename, args=sys.argv[1:])
~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/_main/_binary_stage2_bootstrap.py", line 319, in _run_py_path
runpy.run_path(main_filename, run_name="__main__")
~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "<frozen runpy>", line 287, in run_path
File "<frozen runpy>", line 98, in _run_module_code
File "<frozen runpy>", line 88, in _run_code
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/_main/binary.py", line 4, in <module>
rlocation_wrapper()
~~~~~~~~~~~~~~~~~^^
File "/home/<username>/<reproduction_folder>/library/__init__.py", line 6, in rlocation_wrapper
print(runfiles_obj.Rlocation("library/__init__"))
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/rules_python+/python/runfiles/runfiles.py", line 306, in Rlocation
source_repo = self.CurrentRepository(frame=2)
File "/home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles/rules_python+/python/runfiles/runfiles.py", line 404, in CurrentRepository
raise ValueError(
...<3 lines>...
)
ValueError: /home/<username>/<reproduction_folder>/library/__init__.py does not lie under the runfiles root /home/<username>/.cache/bazel/_bazel_<username>/0123456789abcdef0123456789abcdef/execroot/_main/bazel-out/k8-fastbuild/bin/binary.runfiles
🌍 Your Environment
Operating System:
Output of bazelisk version:
Rules_python version:
🐞 bug report
Affected Rule
python.runfilesRlocation()Is this a regression?
No
Description
When we call
Rlocation()inside of a custom python package without passing in thesource_repo=parameter and import our package for use elsewhere, ifsys.pathincludes a path to our package's code that is outside the runfiles directory, then theRlocation()call will fail.Specifically, this is caused by the code here, which attempts to look up runfiles using the repository mapping of the caller of the
Rlocation()method. Ifsys.pathhas found and run the copy of our python package that resides outside of the runfiles directory, then theRlocation()call is legitimately coming from outside the runfiles directory, causing the underlying call toself.CurrentRepository()to fail.A custom package which calls
Rlocation()shouldn't be required to provide thesource_repo=parameter or else run the risk of error due to being found outside of the runfiles directory due to the configuration ofsys.path.🔬 Minimal Reproduction
MODULE.bazelBUILD.bazelbinary.pylibrary/__init__.pyIn order to have
sys.pathfind the package outside the runfiles directory, we can set thePYTHONPATHenvironment variable to the outer folder containing the package.To reproduce the failure, run:
🔥 Exception or Error
Full traceback:
🌍 Your Environment
Operating System:
Output of
bazelisk version:Rules_python version: