completed easy(random, sum) and attempted medium (pig latin

src/easy/3or5/plain.md

@@ -1 +1,10 @@
 # Plain English Solution
+If you list all the natural numbers below 10 that are multiples of 3 or 5, you'll get 3, 5, 6 and 9. The sum of these multiples is 23.
+
+Find the sum of all the multiples of 3 or 5 below 1000.
+
+1) create a list from 1 - 1000 
+2) Go through each number so we are able to check if they are a multiple of 3 and 5.
+3) When a number is a multiple of 3 and 5, save these values 
+4) create a sum of these values 
+5) return the total value

src/easy/3or5/pseudo.md

@@ -1 +1,6 @@
 # Pseudo Code Solution
+1) create const variable 'find numbers that are multiples of 3 and 5;'
+2) create another const variable for loops
+3) create a loop where the condition is less that 1,000 and adds one - use the push function (adds elements to the end)
+4) Use the modulo % 3 and % 5 in order to get the multiples
+5) get the result

src/easy/digitCount/plain.md

@@ -1 +1,14 @@
 # Plain English Solution
+# Digit Count
+
+Given a number, count the number of digits. For example:
+
+```text
+318 = 3
+92563 = 5
+4666 = 4
+314890 = 6
+```
+
+1) create a list - all numnbers above 0
+2) use count formula so any number will count the number of digits

src/easy/digitCount/pseudo.md

@@ -1 +1,15 @@
+
 # Pseudo Code Solution
+
+
+Given a number, count the number of digits. For example:
+
+```text
+318 = 3
+92563 = 5
+4666 = 4
+314890 = 6
+```
+1) create two const, one to enter any number and two, so the num formula can feed through
+2) the second const - use function called count which equals 0 
+3) use an if statement to return digits

src/easy/factorial/plain.md

@@ -1 +1,8 @@
 # Plain English Solution
+Find the product of all positive integers less than or equal to any given number. This is known as the _factorial_ (denoted by _!_):
+
+`5! = 5 x 4 x 3 x 2 x 1 = 120`
+
+1) create function 
+2) create a list of numbers above 1 by creating a loop
+3) each number entered in the console log, for example, 8, will times all numbers from 1-8 together

src/easy/factorial/pseudo.md

@@ -1 +1,10 @@
 # Pseudo Code Solution
+Find the product of all positive integers less than or equal to any given number. This is known as the _factorial_ (denoted by _!_):
+
+`5! = 5 x 4 x 3 x 2 x 1 = 120`
+
+ 1) create a function called factorial, enter a paramete
+ 2) create a for loop, which starts from 1, and allocate a condition to find numbers above 1
+ 3) assign const with operation of multiplication 
+ 4) create a return, returning the const
+ 5) console.log

src/easy/makeSentence/plain.md

@@ -1 +1,5 @@
 # Plain English Solution
+Given a sentence, capitalise the first letter and add a full stop to the end. However, if the sentence already ends with some form of puncutation, leave it as is.
+
+1) create an array - allocate a sentence inside the array
+2) use the unshift function that capitalises the first letter

src/easy/makeSentence/problem.md

@@ -1,3 +1,4 @@
 # Make Sentence
 
 Given a sentence, capitalise the first letter and add a full stop to the end. However, if the sentence already ends with some form of puncutation, leave it as is.
+

src/easy/makeSentence/pseudo.md

@@ -1 +1,2 @@
 # Pseudo Code Solution
+Given a sentence, capitalise the first letter and add a full stop to the end. However, if the sentence already ends with some form of puncutation, leave it as is.

src/easy/random/plain.md

@@ -1 +1,9 @@
 # Plain English Solution
+Create your own method for generating a random number between two other numbers.
+
+It is common to use _time_ as a means of generating a random number, but there are other ways, too - can you find one?
+
+
+1) choose two random numbers
+2) create a function
+3) create a return that generates the random number

src/easy/random/pseudo.md

@@ -1 +1,8 @@
 # Pseudo Code Solution
+Create your own method for generating a random number between two other numbers.
+
+It is common to use _time_ as a means of generating a random number, but there are other ways, too - can you find one?
+
+1) choose two random numbers
+2) create a function
+3) create a return that generates the random number

src/easy/random/solution.js

@@ -0,0 +1,16 @@
+// //# Pseudo Code Solution
+// Create your own method for generating a random number between two other numbers.
+
+// It is common to use _time_ as a means of generating a random number, but there are other ways, too - can you find one?
+
+// 1) choose two random numbers
+// 2) create a function
+// 3) create a return that generates the random number
+
+let num = 0
+function randomNum (){
+
+   return num = Math.floor(Math.random()*41);
+}
+
+console.log(randomNum())

src/easy/sum/plain.md

@@ -1 +1,9 @@
 # Plain English Solution
+Sum the numbers from 1 to 100.  
+
+For example, to sum the numbers from 1 to 5, you'd have:
+
+1 + 2 + 3 + 4 + 5 = 15
+
+1) create a list from 1 to 100
+2) sum up the numbers from 1 to 100

src/easy/sum/pseudo.md

@@ -1 +1,11 @@
 # Pseudo Code Solution
+Sum the numbers from 1 to 100.  
+
+For example, to sum the numbers from 1 to 5, you'd have:
+
+1 + 2 + 3 + 4 + 5 = 15
+
+
+1) create a const variable 'numbers from 1-100'
+2) create a loop, where the condition is less than 100 and adds 1 each time
+3) create a return

src/easy/sum/solution.js

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+// 1) create a const variable 'numbers from 1-100'
+// 2) create a loop, where the condition is less than 100 and adds 1 each time
+// 3) create a return
+
+let sumOfNums = 0
+
+function num () {
+
+
+for (let i = 1; i <= 100; i++) {
+sumOfNums += i
+}
+
+return sumOfNums
+}
+console.log(num())

src/medium/pigLatin/solution.js

@@ -0,0 +1,27 @@
+// # Pig Latin
+
+// Translate some text to Pig Latin and vice versa.
+
+// English is translated to Pig Latin by taking the first letter of every word, moving it to the end of the word and adding ‘ay’. Therefore, "The quick brown fox" becomes "Hetay uickqay rownbay oxfay".
+
+// var arr = [1, 2, 6, 3, 4, 5];
+//     arr.push(arr.splice(2,4), 1)[0]);
+//     console.log(arr); // [1, 2, 3, 4, 5, 6]
+
+// "hello world"
+// "ellohay orldway"
+
+//Step 1 "hello world"
+//split > [ "hello", "world"
+// Step 2 Hello:       H shifted then pushed to the end
+//step 3 push AY to the end of the ELLOH
+
+var a = ["h","ello"]
+
+    a.push(a.shift());
+    a.push('ay');
+    console.log(a); // [1,2,3,4,5]
+
+
+
+