🧹 Remove dead code comments in parser.c#39
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This PR removes two explanatory comments without introducing any functional defects. All tests pass and the code continues to function correctly. No blocking issues identified.
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Pull request overview
This PR removes two obsolete explanatory comments in parser.c without changing parser behavior.
Changes:
- Removed comments describing the existing backtracking path before parsing an identifier statement as an expression.
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Code Review
This pull request removes obsolete comments in the parse_stmt function of parser.c. However, the reviewer identified a critical bug in the backtracking logic where restoring the parser state (*p = saved_parser) does not restore the underlying lexer state, leading to skipped tokens and parsing failures. A fix is recommended to save and restore the lexer state by value.
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parser.c (355-356)
Critical Bug: Broken Backtracking Logic
While removing these comments cleans up the code, the underlying backtracking logic here is actually broken and will cause parsing failures (such as skipping operators/tokens) on valid inputs.
Why it happens:
Parsercontains a pointer toLexer(Lexer *lex).- At line 302,
Parser saved_parser = *p;only performs a shallow copy of theParserstruct. It does not copy or clone the state of theLexer(lex->posandlex->line). - When
advance(p)is called, the underlyingLexerstate is mutated (advancingpos). - When backtracking occurs here via
*p = saved_parser;, the parser's current token is restored, but the lexer's position remains advanced. - Consequently, the next time
advance(p)is called, the lexer will resume from the advanced position, completely skipping the tokens that were scanned during the lookahead.
Example:
For an input like x + 1:
p->curisx.saved_parsersavesx.advance(p)advances the lexer to+.- Since
+is not(,[, or=, the parser backtracks:*p = saved_parser;(restoringp->curtox). parse_expr(p)is called. It parsesxand then callsadvance(p)to get the next token.- Because
p->lex->poswas not restored,advance(p)reads1instead of+. The+operator is completely lost, leading to a syntax error.
Recommended Fix:
To properly backtrack, you must also save and restore the Lexer state by value:
// At line 302:
Lexer saved_lexer = *p->lex;
Parser saved_parser = *p;
// At line 355:
*p->lex = saved_lexer;
*p = saved_parser;
🎯 What: Removed two explanatory comments at lines 355 and 356 in
parser.cthat were flagged as commented out code blocks.💡 Why: Reduces noise and improves code health by removing flagged code, even if it was technically an explanatory comment. The backtracking logic below is self-explanatory.
✅ Verification: Ran
make testand all tests pass. Removed scratchpad files.✨ Result: Cleaner codebase with no functional changes.
PR created automatically by Jules for task 16083658144594474111 started by @clpi