Solution of 0010 and 0011 done in c language

solution/0000-0099/0010.Regular Expression Matching/README.md

@@ -331,6 +331,44 @@ public class Solution {
 }
 ```
 
+#### C
+
+```c
+#define MAX_LEN 1000
+
+char *ss, *pp;
+int m, n;
+int f[MAX_LEN + 1][MAX_LEN + 1];
+
+bool dfs(int i, int j) {
+    if (j >= n) {
+        return i == m;
+    }
+    if (f[i][j] != 0) {
+        return f[i][j] == 1;
+    }
+    int res = -1;
+    if (j + 1 < n && pp[j + 1] == '*') {
+        if (dfs(i, j + 2) || (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j))) {
+            res = 1;
+        }
+    } else if (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j + 1)) {
+        res = 1;
+    }
+    f[i][j] = res;
+    return res == 1;
+}
+
+bool isMatch(char* s, char* p) {
+    ss = s;
+    pp = p;
+    m = strlen(s);
+    n = strlen(p);
+    memset(f, 0, sizeof(f));
+    return dfs(0, 0);
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->
@@ -579,6 +617,31 @@ class Solution {
 }
 ```
 
+#### C
+
+```c
+bool isMatch(char* s, char* p) {
+    int m = strlen(s), n = strlen(p);
+    bool f[m + 1][n + 1];
+    memset(f, 0, sizeof(f));
+    f[0][0] = true;
+
+    for (int i = 0; i <= m; ++i) {
+        for (int j = 1; j <= n; ++j) {
+            if (p[j - 1] == '*') {
+                f[i][j] = f[i][j - 2];
+                if (i > 0 && (p[j - 2] == '.' || p[j - 2] == s[i - 1])) {
+                    f[i][j] = f[i][j] || f[i - 1][j];
+                }
+            } else if (i > 0 && (p[j - 1] == '.' || p[j - 1] == s[i - 1])) {
+                f[i][j] = f[i - 1][j - 1];
+            }
+        }
+    }
+    return f[m][n];
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0000-0099/0010.Regular Expression Matching/README_EN.md

@@ -330,6 +330,44 @@ public class Solution {
 }
 ```
 
+#### C
+
+```c
+#define MAX_LEN 1000
+
+char *ss, *pp;
+int m, n;
+int f[MAX_LEN + 1][MAX_LEN + 1];
+
+bool dfs(int i, int j) {
+    if (j >= n) {
+        return i == m;
+    }
+    if (f[i][j] != 0) {
+        return f[i][j] == 1;
+    }
+    int res = -1;
+    if (j + 1 < n && pp[j + 1] == '*') {
+        if (dfs(i, j + 2) || (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j))) {
+            res = 1;
+        }
+    } else if (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j + 1)) {
+        res = 1;
+    }
+    f[i][j] = res;
+    return res == 1;
+}
+
+bool isMatch(char* s, char* p) {
+    ss = s;
+    pp = p;
+    m = strlen(s);
+    n = strlen(p);
+    memset(f, 0, sizeof(f));
+    return dfs(0, 0);
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->
@@ -578,6 +616,31 @@ class Solution {
 }
 ```
 
+#### C
+
+```c
+bool isMatch(char* s, char* p) {
+    int m = strlen(s), n = strlen(p);
+    bool f[m + 1][n + 1];
+    memset(f, 0, sizeof(f));
+    f[0][0] = true;
+
+    for (int i = 0; i <= m; ++i) {
+        for (int j = 1; j <= n; ++j) {
+            if (p[j - 1] == '*') {
+                f[i][j] = f[i][j - 2];
+                if (i > 0 && (p[j - 2] == '.' || p[j - 2] == s[i - 1])) {
+                    f[i][j] = f[i][j] || f[i - 1][j];
+                }
+            } else if (i > 0 && (p[j - 1] == '.' || p[j - 1] == s[i - 1])) {
+                f[i][j] = f[i - 1][j - 1];
+            }
+        }
+    }
+    return f[m][n];
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0000-0099/0010.Regular Expression Matching/Solution.c

@@ -0,0 +1,33 @@
+#define MAX_LEN 1000
+
+char *ss, *pp;
+int m, n;
+int f[MAX_LEN + 1][MAX_LEN + 1];
+
+bool dfs(int i, int j) {
+    if (j >= n) {
+        return i == m;
+    }
+    if (f[i][j] != 0) {
+        return f[i][j] == 1;
+    }
+    int res = -1;
+    if (j + 1 < n && pp[j + 1] == '*') {
+        if (dfs(i, j + 2) || (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j))) {
+            res = 1;
+        }
+    } else if (i < m && (ss[i] == pp[j] || pp[j] == '.') && dfs(i + 1, j + 1)) {
+        res = 1;
+    }
+    f[i][j] = res;
+    return res == 1;
+}
+
+bool isMatch(char* s, char* p) {
+    ss = s;
+    pp = p;
+    m = strlen(s);
+    n = strlen(p);
+    memset(f, 0, sizeof(f));
+    return dfs(0, 0);
+}

solution/0000-0099/0010.Regular Expression Matching/Solution2.c

@@ -0,0 +1,20 @@
+bool isMatch(char* s, char* p) {
+    int m = strlen(s), n = strlen(p);
+    bool f[m + 1][n + 1];
+    memset(f, 0, sizeof(f));
+    f[0][0] = true;
+
+    for (int i = 0; i <= m; ++i) {
+        for (int j = 1; j <= n; ++j) {
+            if (p[j - 1] == '*') {
+                f[i][j] = f[i][j - 2];
+                if (i > 0 && (p[j - 2] == '.' || p[j - 2] == s[i - 1])) {
+                    f[i][j] = f[i][j] || f[i - 1][j];
+                }
+            } else if (i > 0 && (p[j - 1] == '.' || p[j - 1] == s[i - 1])) {
+                f[i][j] = f[i - 1][j - 1];
+            }
+        }
+    }
+    return f[m][n];
+}

solution/0000-0099/0011.Container With Most Water/README.md

@@ -262,6 +262,33 @@ class Solution {
 }
 ```
 
+#### C
+
+```c
+int min(int a, int b) {
+    return a < b ? a : b;
+}
+
+int max(int a, int b) {
+    return a > b ? a : b;
+}
+
+int maxArea(int* height, int heightSize) {
+    int l = 0, r = heightSize - 1;
+    int ans = 0;
+    while (l < r) {
+        int t = min(height[l], height[r]) * (r - l);
+        ans = max(ans, t);
+        if (height[l] < height[r]) {
+            ++l;
+        } else {
+            --r;
+        }
+    }
+    return ans;
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0000-0099/0011.Container With Most Water/README_EN.md

@@ -259,6 +259,33 @@ class Solution {
 }
 ```
 
+#### C
+
+```c
+int min(int a, int b) {
+    return a < b ? a : b;
+}
+
+int max(int a, int b) {
+    return a > b ? a : b;
+}
+
+int maxArea(int* height, int heightSize) {
+    int l = 0, r = heightSize - 1;
+    int ans = 0;
+    while (l < r) {
+        int t = min(height[l], height[r]) * (r - l);
+        ans = max(ans, t);
+        if (height[l] < height[r]) {
+            ++l;
+        } else {
+            --r;
+        }
+    }
+    return ans;
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0000-0099/0011.Container With Most Water/Solution.c

@@ -0,0 +1,22 @@
+int min(int a, int b) {
+    return a < b ? a : b;
+}
+
+int max(int a, int b) {
+    return a > b ? a : b;
+}
+
+int maxArea(int* height, int heightSize) {
+    int l = 0, r = heightSize - 1;
+    int ans = 0;
+    while (l < r) {
+        int t = min(height[l], height[r]) * (r - l);
+        ans = max(ans, t);
+        if (height[l] < height[r]) {
+            ++l;
+        } else {
+            --r;
+        }
+    }
+    return ans;
+}