How to pass in the feed xml files only the first part of the post?

[ilg-ul]

I noticed that in the feed xml files, the entire content of the post is passed as the <content:encoded> element.

My posts are large and I would like to pass only the first part, up to the <!-- truncate --> line.

Initially I thought that I can trim the content of the post via feedOptions.createFeedItems, but this was not effective, since the content is not used, instead the generated html is read from a file.

[ilg-ul]

Any suggestion?

[slorber]

but this was not effective, since the content is not used, instead the generated html is read from a file.

I don't know what you mean here. Show me the code of your attempt and try to explain better.

---

I'm not sure it's a good idea to reparse the html content string to truncate it (you can if you really want to, with cheerio for example), but you can use any blog post metadata or custom front matter to populate the feed item content quite easily:

              createFeedItems: async (params) => {
                const feedItems = await params.defaultCreateFeedItems(params);
                return feedItems.map((feedItem, index) => {
                  const blogPost = params.blogPosts[index]!;
                  return {
                    ...feedItem,
                    content: blogPost.metadata.description,
                  };
                });
              },