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feat(CopyLyrics): 可以预览复制的歌名和歌手 #950
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这里的
else if (showArtist)条件是多余的,并且最后的return ""是无法访问到的代码。因为函数开头已经判断了showSongName和showArtist都为false的情况并提前返回,所以如果代码能执行到这里,showArtist必定为true。你可以用一个else语句来简化这部分逻辑,这样代码更简洁,也移除了无法访问到的代码。There was a problem hiding this comment.
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原有逻辑,未改动