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Copy file name to clipboardExpand all lines: content/applied-math/information-theory/01-discrete-entropy.tex
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\end{corollary}
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\begin{theorem}
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\begin{theorem}[Uniform distribution maximizes entropy]
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A \@{random-variable} has the most \@{entropy} when the \@{elements} of its alphabet are all equally likely to occur.
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% TODO (path B): re-derive from D(p || u) = log|X| - H(X) >= 0, with u uniform (Cover and Thomas Thm 2.6.4). The current proof below uses Lagrange multipliers.
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\end{theorem}
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\begin{proof}
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\begin{theorem}
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The \@{uncertainty} of $Y$ is never increased by knowledge of $X.$ It will be decreased unless $X$ and $Y$ are independent events, in which case it is not changed.
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% TODO (path B): re-derive from I(X;Y) >= 0 (Cover and Thomas Thm 2.6.5). The current proof below uses subadditivity and the chain rule, which reverses the intended dependency.
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\end{theorem}
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\begin{proof}
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\end{intuition}
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\begin{theorem}[Concavity of Entropy]
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$H(p)$ is a \@{concave function} of $p.$
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\end{theorem}
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\begin{proof}
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Let $u$ be the uniform distribution on $|\mathcal{X}|$ outcomes. Then from the definition of @{relative-entropy},
and by \@{convexity of relative entropy}, \@{entropy} is a \@{concave function}.
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\end{proof}
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\begin{intuition}
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The intuition is that mixing distributions can never decrease uncertaintity.
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\includegraphics[alt={Convexity of Relative Entropy}]{concavity-of-entropy.png}
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The image above was generated using GPT-5.6 Sol.
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We already proved \@{Uniform distribution maximizes entropy} using Lagrangian multipliers, but the proof above shows it in another way. If $p = u,$ then $D(p \| u) = 0,$ and since $\log{|\mathcal{X}|}$ is constant in $|\mathcal{X}|,$$H$ is maximized by $u$.
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\end{intuition}
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\begin{theorem}[Concavity and Convexity of Mutual Information]
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