contract without schema?

[iamyuu]

Hi, I want to use orpc only for clients, but I don't want to add extra bundle to parse the response, is that possible? e.g.

// or maybe you can use `HttpError` as the default error response?
type HttpError = {
  message: string
}

type FilterTodo = {
  search: string
}

type Todo = {
  id: number
  title: string
  completed: boolean
}

const contract = oc.router({
  todo: oc.router({
    all: oc.route({ method: 'GET', path: '/todos' })
      .input<Partial<FilterTodo>>()
      .output<Todo[], HttpError>(),

    create: oc
      .route({ method: 'POST', path: '/todos' })
      .input<Omit<Todo, 'id'>>()
      .output<Todo, HttpError>(),

    completeById: oc
      .route({ method: 'PUT', path: '/todos/{id}' })
      .output<Todo, HttpError>(),
  }),
});

Thanks!

[dinwwwh]

We can do this:

import type { StandardSchemaV1 } from '@standard-schema/spec'
import type { ZodType, ZodTypeDef } from 'zod'
import { z } from 'zod'
import { oc } from '.'

// for universal way
export function type<T>(): StandardSchemaV1<T, T> {
  return undefined as any
}

// or specific with zod
export function type<T>(): ZodType<T, ZodTypeDef, T> {
  return z.custom<T>()
}

type FilterTodo = {
  search: string
}

type Todo = {
  id: number
  title: string
  completed: boolean
}

const contract = oc.route({ method: 'GET', path: '/todos' })
  .input(type<Partial<FilterTodo>>())
  .output(type<Todo[]>())
  .errors({
    HTTP_ERROR: {
      message: 'default error message',
    },
  })

But for error response HttpError you must define it inside .errors

[iamyuu]

I see, I think type should be built it right? like ts-rest

[dinwwwh]

I see, I think type should be built it right? like ts-rest

Yes, I will do that