r.pipe(z).pipe(w) should behave the same as pipeline(r, z, w)

[richytong]

To me, the r.pipe(z).pipe(w) expression is a pipeline:

const r = fs.createReadStream('file.txt');
const z = zlib.createGzip();
const w = fs.createWriteStream('file.txt.gz');

r.pipe(z).pipe(w);

When a stream is piped to another stream, that should create a pipeline, and be functionally equivalent to the expression pipeline(r, z, w).

const r = fs.createReadStream('file.txt');
const z = zlib.createGzip();
const w = fs.createWriteStream('file.txt.gz');

pipeline(r, z, w);

pipe returning the writable stream is nonintuitive. It should return a new Pipeline object. And perhaps we can deprecate pipeline.